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Reika [66]
3 years ago
9

The question is in the picture

Mathematics
2 answers:
Nataly [62]3 years ago
7 0

Answer:

  • 1/12

Step-by-step explanation:

The spinner includes 12 numbers, 1 through 12.

<u>The probability of getting each number is equal and is one out of 12:</u>

  • P(11) = 1/12
Hatshy [7]3 years ago
3 0

Answer:

1/12 should be the answer

Step-by-step explanation:

Please give  brainliest :)

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Group of 7 people spend 33.50 movie tickets 6.50 adults and 3.50 for child ticket. Which system of equation could be used to fin
kramer
The answer is
x + y = 7
6.50x + 3.50y = 33.50

x - the number of adult tickets
y - the number of child tickets

<span>Group of 7 people: x + y = 7
</span> 6.50 adults and 3.50 for child ticket cost <span>33.50: 6.50x + 3.50y = 33.50

So, we have two equations:
</span>x + y = 7
6.50x + 3.50y = 33.50
7 0
3 years ago
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My dog, Petey weighs 75 pounds. Last summer he weighed 65 pounds. What percent of his weight did he gain?
OLEGan [10]

Answer:

he gain 10%

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Help please! Could you put an explanation as well?
Lisa [10]

Answer:

y=-(4x/3) -1

Step-by-step explanation:

Slope=m= -4/3

y intercept = c = -1

now using equation;

y= mx+c

y= (-4/3)x+(-1)

y=-(4x/3) -1

4 0
2 years ago
Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

Answer:

Required total charge is 256\pi coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

x^2=y^2\leq 16 so that the charge density at (x,y) is,

\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta

=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

3 0
3 years ago
How do u solve 94=y/4-18. What do get for y.
Alexus [3.1K]
94=y/4-18
first you would +18 on each side with a result of 112=y/4 then you would x4 on each side with an end result of 448=y

y=448
3 0
2 years ago
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