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3 years ago

Pls help with odd problems only pls

Mathematics

1 answer:

almond37 [142]3 years ago

5 0

I'm not sure about questions 7-10 tho, very sorry

Step-by-step explanation:

11) 5/7

12) 1/4

13) 7/10

14) 3/4

15) 2/9

16) 2/5

17) 13/30

18) 27/50

19) 5/16

20) 4/15

21) 1/24

22) 7/12

23) 1/20

24) 8/15

25) 11/45

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a farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. no fencing is needed along the bar

xenn [34]

The constraint for the maximum enclosed area is the amount the farmer is

willing to spend on fencing.

The width of the plot that will give the most area, y = 83. $\underline{\overline 3}$ feet

The length of the plot that will give the most area, y = 125 feet

Reasons:

The given parameters are;

The cost of fencing per foot = $20

The maximum amount the farmer is willing to spend = $5000

Number of sides of fencing = 3 sides

Cost of the west side of the = Split with neighbor

Solution:

Let, y, represent the length of the fence, and let x represent the width of

the fence, we have;

Length of fence required = y + 2·x

Cost of the fence = 20·y + 20·x + (20÷2)·x = 20·y + 30·x

Therefore;

Maximum amount to be spent on the fence, 5000 = 20·y + 30·x

$\therefore y = \dfrac{5000 - 30 \cdot x}{20} = 250 - \dfrac{3}{2} \cdot x$

$y = \mathbf{250 - \dfrac{3}{2} \cdot x}$

Area of a rectangle = Length × Width

The enclosed rectangular area of the fencing, A = y × x

$\therefore A = \left(250 - \dfrac{3}{2} \cdot x\right) \cdot x = 250 \cdot x - \dfrac{3}{2} \cdot x^2$

$\therefore A = -\mathbf{ \dfrac{3}{2} \cdot x^2 + 250 \cdot x}$

The leading coefficient of the quadratic function of the area is negative,

therefore, the function only has a maximum point.

At the point of the most area, the slope, $\dfrac{dA}{dx} = 0$

Finding the value of x at the maximum point, we get;

$\dfrac{dA}{dx} = \mathbf{ \dfrac{d}{dx} \left( 250 \cdot x - \dfrac{3}{2} \cdot x^2\right)} = 250- 3 \cdot x = 0$

Therefore;

$\mathrm{ The \ width \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ x = \dfrac{250}{3} \ feet = \underline{83.\overline 3 \ feet}$

$\mathrm{ The \ length \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ y = 250 - \dfrac{3}{2} \times \dfrac{250}{3} = 125$

The length of the plot that will give the most area, y = 125 feet

Learn more here:

brainly.com/question/16337916

brainly.com/question/16545343

6 0

3 years ago

3250 - M = 1500 + 2(M - 500)

bija089 [108]

Answer:

M=916 2/3

Step-by-step explanation:

3250-m=1500+2(m-500)

3250-M=1500+2m-1000

3250-M=2M+500

3M=2750

M=916 2/3

5 0

3 years ago

Read 2 more answers

Brenda's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 3 senior citizen ticket

Feliz [49]

We can form two equations, let the price of a senior ticket be s and the price of a child ticket be c.
We have from day 1:
A: 3s + 9c = 75
And from day 2:
B: 8s + 5c = 67

Now we can rewrite A as:
A: 24s + 72c = 600
And can rewrite B as:
B: 24s + 15c = 201

Now A-B can be written as:
A-B: 57c = 399

So c = 7

Now substituting this back into A we get:
A: 3s + 63 = 75
A: 3s = 12

So s = 4

We have the price of a senior ticket is $4 and the price of a child ticket is $7

3 0

3 years ago

Need answer ASAP please! X= 1 3 7

Trava [24]

Answer: i believe its 3

Step-by-step explanation:

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3 years ago

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Help HeLp HelP HELLPPPP!!

julsineya [31]

Answer: the circle wth 3 covered goes in 1/2 and the rectangle and the other circle go in 3/5 the small square with 2 covered goes in other and the long line of squares goes in other

Step-by-step explanation:

6 0

3 years ago

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Pls help with odd problems only pls ​

Pls help with odd problems only pls