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denis23 [38]
3 years ago
5

Please help me!!!!!!

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

Step-by-step explanation:

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I rlly need help with this guys please help me
makvit [3.9K]
24.1 times24 times 3.5times 2. Is 271ft2
6 0
3 years ago
Does dose anyone know how to solve this?
solniwko [45]

Answer:

Width of rectangle = 6 m

Length of rectangle = 11 m

Step-by-step explanation:

Let width of rectangle = w

Length of rectangle = 3w-7

Area of rectangle = 66 m²

We need to find length and width of rectangle

The formula used is: Area=Length \times Width

Putting values and finding w

Area=Length \times Width\\66=(3w-7)(w)\\66=3w^2-7w\\3w^2-7w-66=0\\

Solve using quadratic formula: w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

We have a=3, b=-7, c=-66

Putting values and finding w

w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\w=\frac{-(-7)\pm\sqrt{(7)^2-4(3)(-66)}}{2(3)}\\w=\frac{7\pm\sqrt{49+792}}{6}\\w=\frac{7\pm\sqrt{841}}{6}\\w=\frac{7\pm29}{6}\\w=\frac{7+29}{6}\:,\:w=\frac{7-29}{6}\\w=6, w=-3.6

We get values of w as w=6 and w=-3.6

As we know width cannot be negative, so considering w = 6

So, Width = 6

Length = 3w-7 = 3(6)-7 = 18-7 = 11

So, Width of rectangle = 6 m

Length of rectangle = 11 m

6 0
3 years ago
What is the range of the function?
Grace [21]

Answer:

the is c because the answer

6 0
3 years ago
Read 2 more answers
A soccer club spent $97.50 on trophies from a custom trophy company. The cost of manufacturing x custom trophies is $18.50 for t
Tomtit [17]
They bought 5 trophies total

1st trophy cost $37.50
($18.50+$12.50+$4+$2.50=$37.50)
Each additional trophy cost $15
($12.50+$2.50=$15)

They spent $97.50 total
$97.50-$37.50=$60
Additional trophies $15
$15*X=$60
4 trophies=$60+$37.50 for 1st trophy
$60+$37.50=$97.50


6 0
4 years ago
I'm so confused on how to even start my homework. I'm so confused and this is due soon, so please help me as soon as possible. I
7nadin3 [17]
Well i ll give u some tips
1-u should know the formulas for calculating different objects areas
2-find the length of their sides or diagonals(which are needed on the formula)
3-calculate the area

for example the triangle on the picture
1-s=leg1*leg2/2
2-the length of:leg1=10-3=7,,leg2=7-1=6
3-s=7*6/2=21
4 0
3 years ago
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