Question

>
Find the roots of the equation x2 – 3x – m (m + 3) = 0, where m is a constant.​

$\:$

Answer 1

Answer:-m or m+3

Step-by-step explanation:

$x^{2} -3x -(m^{2}+3m) =0\\\\x^{2} -3x -m^{2} -3m=0$

$x^{2} -m^{2} -3x - 3m=0$

Applying difference of two squares

⇒($x^{2} -m^{2}$)=(x+m)(x-m)

Substituting this for ($x^{2} -m^{2}$)

Factorising -3x-3m=-3(x+m)

(x+m)(x-m)-3(x+m)=0

since we have double (x+m),we'll pick one

⇒(x+m)=0

or (x-m-3)=0

⇒x=-m or x= m+3