Answer:
Advance ticket costs $25
Same-day ticket costs $20
Step-by-step explanation:
Let x = the price of one the advance ticket.
Let y = the price of one same-day ticket.
The combined cost of one advance ticket and one same-day ticket is $ 45. This means
x + y = 45 - - - - - - 1
For one performance, 30 advance tickets and 20 same-day tickets were sold. The total amount paid for the tickets was $ 1150. This means
30x + 20y = 1150 - - - - - - - - -2
From equation 1, x = 45- y
Put x = 45- y in equation 2
30( 45-y) + 20y = 1150
1350 - 30y + 20y = 1150
-10y = 1150-1350
-10y = -200
y = 200/10 = $20
x = 45-y
x =45-20= $25
Advance ticket costs $25
Same-day ticket costs $20
Answer:
Its C
Step-by-step explanation:
15 is the answer because 8-5 is 3 and 3 and 4 is 12 so 12 plus 3 is 15
Yes the answer I should be 10.
