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Anika [276]
3 years ago
5

John was traveling 1700 feet in 20 seconds. How fast was the car going in miles per hour

Mathematics
1 answer:
bagirrra123 [75]3 years ago
6 0

Answer:

612000

Step-by-step explanation:

(20*3)*60=360

360*1700=612000

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Combine like terms for <br> (3x²+2x²-5x+7)+(4x²+2x-3)
horsena [70]

Answer:

9x^2-3x+4

Step-by-step explanation:

(3x^2+2x^2-5x+7)+(4x^2+2x-3)

5x^2-5x+7+4x^2+2x-3

5x^2+4x^2-5x+2x+7-3

9x^2-3x+7-3

9x^2-3x+4

5 0
3 years ago
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Find k such that the equation kx^2+x+25k=0 has a repeated solution.
Paha777 [63]
Ill try to answer your question
4 0
3 years ago
∠QPS is a right angle and m∠QPR = 71°, what is m∠RPS?
natta225 [31]

Answer: <RPS = 161

Step-by-step explanation:

P is the common vertex in all of these angles. From this we know that these have to be adjacent angles (<QPR and <QPS) that equal the whole angle (<RPS)

<QPR+<QPS= <RPS

71+90= 161

(<QPS is a right angle. Right angles are equal to 90 degrees.)

8 0
2 years ago
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
A certain number of sixes and nines is added to give a sum of 126; if the number of sixes and nines is interchanged, the new sum
galina1969 [7]

Answer:

Original number of sixes = 6

Original number of nines = 10

Step-by-step explanation:

We are told in the question that:

A certain number of sixes and nines is added to give a sum of 126

Let us represent originally

the number of sixes = a

the number of nines = b

Hence:

6 × a + 9 × b = 126

6a + 9b = 126.....Equation 1

If the number of sixes and nines is interchanged, the new sum is 114.

For this second part, because it is interchanged,

Let us represent

the number of sixes = b

the number of nines = a

6 × b + 9 × a = 114

6b + 9a = 114.......Equation 2

9a + 6b = 114 .......Equation 2

6a + 9b = 126.....Equation 1

9a + 6b = 114 .......Equation 2

We solve using Elimination method

Multiply Equation 1 by the coefficient of a in Equation 2

Multiply Equation 2 by the coefficient of a in Equation 1

6a + 9b = 126.....Equation 1 × 9

9a + 6b = 114 .......Equation 2 × 6

54a + 81b = 1134 ........ Equation 3

54a + 36b = 684.........Equation 4

Subtract Equation 4 from Equation 3

= 45b = 450

divide both sides by b

45b/45 = 450/45

b = 10

Therefore, since the original the number of nines = b,

Original number of nines = 10

Also, to find the original number of sixes = a

We substitute 10 for b in Equation 1

6a + 9b = 126.....Equation 1

6a + 9 × 10 = 126

6a + 90 = 126

6a = 126 - 90

6a = 36

a = 36/6

a = 6

Therefore, the original number of sixes is 6

7 0
3 years ago
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