Wait so is Paula 12? If so then in months she would be 144months
If the rectangular field has notional sides X and y then it has area
A(x) =xy { =6•10^6 sq ft }
The length of fencing required, if
x
is the letter that was arbitrarily assigned to the side to which the dividing fence runs parallel, is:l (x) = 3x +2y
It matters not that the farmer wishes to divide the area into 2 exact smaller areas.
Assuming the cost of the fencing is proportional to the length of fencing required, then
C(x)=a L (x)
To optimise cost, using the Lagrange Multiplier
λ
, with the area constraint :
So the farmer minimises the cost by fencing-off in the ratio 2:3, either-way
I don’t get what it is asking
Hi there,
The answer is 1/3 cup per teaspoon. Here’s how...
All you have to do is divided 2/3 by 2.
We have to put a 1 under the 2 to at least represent it as a fraction.
2/3 / 2/1
Next we flip 2/1 into 1/2.
2/3 / 1/2
Now we are going to multiply.
2x1=2
3x2=6
We get 2/6, simplifying that we get 1/3 cup per teaspoon.
The answer to this is -15