Answer:
110
Step-by-step explanation:
Let the three numbers be 100, 110 and 120
100 + 110 + 120 = 330
Total numbers = 3
Given the following information, determine if one of the brands is a better buy. Brand A: 14 ounces for $44. 66 Brand B: 20 ounc
1 answer:
Division is one of the basic mathematical operations. The cost of Brand A and B is the same.
<h3>What is division?</h3>The division is one of the most basic arithmetic operations. It is used to find the number of times a number is been added to itself.
Given to us
Brand A: 14 ounces for $44.66
Brand B: 20 ounces for $63.80
To compare the two brands we will find the cost of one ounce for each brand.
For Brand A,
The cost of 14 ounces is $44.66, therefore,
For Brand B,
The cost of 20 ounces is $63.80, therefore,
From the above two values, we can conclude that the cost of Brand A and B is the same.
Learn more about Division:
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Answer:
The passing score is 645.2
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If the board wants to set the passing score so that only the best 10% of all applicants pass, what is the passing score?
This is the value of X when Z has a pvalue of 1-0.1 = 0.9. So it is X when Z = 1.28.
The passing score is 645.2
Answer:
(a) The sample space is {00, 0, 1, 2, . . . , 30}.
(b) If the wheel is spun 1,000 times, it is expected about 31 of those times to result in the ball landing in slot 3.
(c) If the wheel is spun 100 times, it is expected about 47 of those times to result in the ball landing in an odd number.
Step-by-step explanation:
We are given that in the game of roulette, a wheel consists of 32 slots numbered 00, 0, 1, 2, . . . , 30.
To play the game, a metal ball is spun around the wheel and is allowed to fall into one of the numbered slots.
(a) The sample space is {00, 0, 1, 2, . . . , 30} which means the metal ball can land on any of these numbers.
(b) As we know that there is an equal probability of the metal ball landing on any of the slots marked in the sample space.
Total number of slots = 32
Number of slots marked with 3 = 1
So, the probability that the metal ball falls into the slot marked 3 is given by = = 0.031 or 3.1%
This means that if the wheel is spun 100 times, it is expected about 3.1 of those times to result in the ball landing in slot 3.
So, if the wheel is spun 1,000 times, it is expected about 31 of those times to result in the ball landing in slot 3 because (0.031 1000) = 31.
(c) As we know that the odd slot in the given sample space is {1, 3, 5,......, 29}.
Total number of slots = 32
Number of odd slots = 15
So, the probability that the metal ball lands in an odd slot is given by = = 0.47 or 47%.
This means that if the wheel is spun 100 times, it is expected about 47 of those times to result in the ball landing in an odd number.