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densk [106]
3 years ago
9

Can somebody help me please

Mathematics
2 answers:
irina1246 [14]3 years ago
5 0
The correct answer is 67 to the third power
Inga [223]3 years ago
3 0
The correct answer is 67 to the three one hopes this help
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Which is greater 80 oz or 5 lb
Len [333]
There the same thing they both  weigh the same thing hope it helps and have a great day!
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3 years ago
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PLZ ANSWER APSP IM IN THE TEST RN!!!
olchik [2.2K]

Answer:

x = 38

y = 25

Step-by-step explanation:

To find x, you do

(2x + 5) = (3x - 33)

Subtract 2x from both sides to isolate x on one side, you get:

5 = (x - 33)

Add 33 to both sides to separate the normal number from the x, you get:

38 = x

From there, you plug x into one of the equations

2(38) + 5

The answer's 81, meaning that angle is 81 degrees. Using supplementary angles, you can find that angle ACD = 99, which you can use to find angle BCE. You'll get this equation:

(4y - 1) = 99

Add one to both sides to get rid of it, you get:

4y = 100

Divide by four, to get the y all alone:

y = 25

I hope this helped!

8 0
3 years ago
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Value expression 0.5*2
topjm [15]
0.5*2=1


Explanation: 0.5+0.5 =1
4 0
4 years ago
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What does this graph tell you about the price of cinnamon
LenaWriter [7]
I think the answer is 2 because the unit price = price/total amount or weight

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3 years ago
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) If the average cost function for a company is given by C(x) = 0.2x + 20x −1 + 75, nd what level of production produces the low
Stells [14]

Answer:

The correct answer is 10 for lowest average cost and the cost function is 0.2x^{2} + 75x + 20.

Step-by-step explanation:

Average cost function is given by = \frac{Cost}{Quantity} = C(x) = 0.2x + \frac{20}{x} +75.

For minimizing we need to find \frac{d}{dx}C(x) = 0.

⇒ \frac{d}{dx}C(x) = 0.2 - \frac{20}{x^{2}}.

⇒ \frac{20}{x^{2}} = 0.2

⇒ x^{2} = 100.

⇒ x = ±10

⇒ x = 10 ; cost cannot be negative.

Second order derivative is positive which implies the average cost minimizes.

Original cost function is given by C(x) × x = 0.2x^{2} + 75x + 20.

5 0
3 years ago
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