Initially, Charlotte owes $7680. She finishes her payments after a total of 6 + 36 = 42 months. Using a simple compounding formula, the amount she owes is worth P at the end of 42 months, where P is:
P = 7680 * (1 + .2045/12)^42 = 15616.67379
Now, the first installment she pays (at the end of six months) is paid 35 months in advance of the end, so it is worth x * (1 + .2375/12)^35 at the end of her loan period.
Similarly, the second installment is worth x * (1 + .2375/12)^34 at the end of the loan period.
Continuing, this way, the last installment is worth exactly x at the end of the loan period.
So, the total amount she paid equals:
x [(1 + .2375/12)^35 + (1 + .2375/12)^34 + ... + (1 + .2375/12)^0]
To calculate this, assume that 1+.2045/12 = a. Then the amount Charlotte pays is:
x (a^35 + a^34 + ... + a^0) = x (a^36 - 1)/(a - 1)
Clearly, this value must equal P, so we have:
x (a^36 - 1)/(a - 1) = P = 15616.67379
Substituting, a = 1 + .2045/12 and solving, we get
x = 317.82
If what you are trying to do here is isolate <em>b,</em> multiply both sides by 2. This cancels out the one half on the side with the <em>b. </em>Then, divide both sides of the equation by h. The End result should be B = 2A/h.
First, draw a diagram of a kite with sides GHIJ. The sides GH, HI, IJ, and JG are the sides. The diagonals can be determined by connecting the opposite sides. J and H, G and I. Therefore, the diagonals for the Kite GHIJ is JH and GI.
Answer:
When we know all 3 sides we use the law of cosines
a = 47
b = 11
c = 38
cos (A) = (b^2+c^2-a^2) / (2bc)
cos (A) = -0.7703349282
Angle A = 140.38
cos (B) = (a^2 + c^2 -b^2) / (2ac)
cos (B) = 0.9888017917
Angle B = 8.5826 degrees
cos (C) = (a^2 + b^2 -c^2) / 2ab
cos (C) = 0.8568665377
cos (C) = 31.033 degrees
Angle W would be the smallest angle so it equals
31.033 degrees or rounded to nearest tenth
31.03
Step-by-step explanation:
Answer:
30?
Step-by-step explanation:
The area of the triangle is 30 but i dont know what the area of a semi circle is.
