<span>Inertia is defined as "the tendency for a body to resist acceleration; the tendency of a body at rest to remain at rest or of a body in motion to stay in motion in a straight line unless disturbed by an external force" Therefore, both will have the same inertia since they have the same mass.</span>
Answer: 0.28
Step-by-step explanation:
Answer: 44 miles
WORKINGS
Given,
The distance between Indianapolis and Lima, IL = 173 miles
The distance between Indianapolis and Dayton, ID = 165 miles
The distance between Dayton and Lima, DL is unknown
Since there are straight roads connecting the three cities, the connection between them form a right angles triangle.
The right angle is at Dayton
The hypotenuse is the distance between Indianapolis and Lima, IL
Therefore IL^2 = ID^2 + DL^2
173^2 = 165^2 + DL^2
DL^2 = 173^2 – 165^2
DL^2 = 29929 – 27225
DL^2 = 2704
DL = 52 miles
Therefore, The distance between Dayton and Lima, DL = 52 miles
The question is asking how many more miles would Meg drive if she stopped in Dayton first than if she drove directly to Lima.
That is, Distance of Indianapolis to Dayton + Distance of Dayton to Lima – Direct distance of Indianapolis to Lima
That is, ID + DL – IL
= 165 miles + 52 miles – 173 miles
= 217 miles – 173 miles
= 44 miles
Therefore, Meg would drive 44 more miles if she stopped in Dayton first than if she drove directly to Lima.
Answer:
The answer is below
Step-by-step explanation:
The volume of a box with a length of l, width of w and a height of h is given by the formula:
volume of the box = length * width * height = lwh
The volume of a cylinder with a height of h, and radius r is given by the formula:
volume of the cylinder = π * radius² * height = πr²h
Since the box and the cylinder have the same height and the cylinder is wide enough for the box to be placed inside, this means that the box has a volume greater than that of the cylinder. Hence:
If the box can take 8 cups, the cylinder would be able to take 10 cups.
Answer:
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General Formulas and Concepts:
<u>Algebra I</u>
Terms/Coefficients
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Quotient Rule]: ![\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B%5Cfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%20%5D%3D%5Cfrac%7Bg%28x%29f%27%28x%29-g%27%28x%29f%28x%29%7D%7Bg%5E2%28x%29%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Derivative Rule [Quotient Rule]:

- Basic Power Rule:

- Exponential Differentiation:

- Simplify:

- Rewrite:

- Factor:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation