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2 years ago

15

Find a 3\frac{1}{2}% commision on a sale of $2,500

2 answers:

mafiozo [28]2 years ago

4 0

Answer:

the commison is $175

hope it helps you

Arisa [49]2 years ago

3 0

Answer:

$3\frac{1}{2}$

$= 7$

Now,

7℅ of 2500

$\frac{7}{100} \times 2500$

$7 \times 25$

$= 175$

Commision=$175

hope it helps you :)

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Lewa's hiking backpack weighs 5 pounds less than 1/2 the weight of alani's hiking backpack write an expression to describe the w

aleksandrvk [35]

A(1/2)-5=L is what I came up with.

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3 years ago

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Which of the following graphs shows the solution for the inequality<br> y-4> 2(x+2)?

timofeeve [1]

Answer:

Answer:

Graph C shows the solution for the inequality

Step-by-step explanation:

y - 4 > 2(x + 2)

y > 2x + 4 + 4

y > 2x + 8

Let y = 2x + 8, Then

X-intercept (0, 8)

Y-intercept (-4, 0)

Since the inequality sign is > we use broken line.

Put, (0, 0)

y > 2x + 8

0 > 0+ 8

0 > 8 Which is false

so, the answer will be above the broken line

Hence , Graph C shows inequality

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2 years ago

A 45 foot ladder is leaning against a building. If the bottom of the ladder is 27 feet from the base of the building, how tall i

taurus [48]

Answer:

The height of building to the nearest foot is h = 36 foot

Step-by-step explanation:

We have given,

Length of ladder leaning against a building, l = 45 foot

Bottom length between ladder and the building , b = 27

Now, we need to find the height of building to the nearest foot.

Let the height of building be h.

Using Pythagoras theorem,

$l^{2} = b^{2} +h^{2}$

Here, l = 45 , b = 27 and h =?

So,

$45^{2} = 27^{2} +h^{2}$

h² = 45² - 27²

h = √(45² - 27²)

h = 36

The height of building to the nearest foot is h = 36 foot

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3 years ago

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Paul [167]

Probably:

True.

Probably.

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3 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

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3 years ago

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