Answer:
T= 4p-18-pr
Step-by-step explanation:
Let X be the number of defective transistors. Let p be the probability that defective transistor.
P(defective transistor) = 0.04
P(non defective ) = 1- 0.04 = 0.96
A random sample of size 30 is tested for defects and we want to find probability of no defective transistor
P(No defective transistor) = P(X= 0)
Here X follows binomial distribution with parameters n=30 and p=0.04
The Binomial probability function with parameters n and p is
P(X=x) =
P(X=0) =
Using n=30 and p=0.04
P(X=0) =
P(X=0) = 1*1*(0.96)^30
P(X=0) = 0.2938
The probability that there are no defective transistors in the sample is 0.2938
Answer:
To write a linear expression in standard form, rearrange the terms in alphabetical order.
×
But, if you need to write it in scientific notation, the answer is 2,900.
Answer:
UGANDA FOREVEA
Step-by-step explanation:
80 questions... 24 divided by .3