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Vedmedyk [2.9K]
3 years ago
6

Find the equation of the exponential function represented by the table below:

Mathematics
1 answer:
NARA [144]3 years ago
4 0

Answer:

y=0.1(4)^x

Step-by-step explanation:

Exponential functions are represented by the formula y=a(b)^x, where a is the initial value, and b is the multiplier.

Here, we can see that when x = 0, or our initial value, y = 0.1.

Thus, a = 0.1.

Since b is the multiplier, or like the slope, we can do 0.4/0.1 and get 4 for our multiplier.

Now plug everything into the formula y=a(b)^x\\y=0.1(4)^x

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Select the correct numerator 7/9 - ?/27
damaskus [11]

Answer:

21

Step-by-step explanation:

27÷3 is 9 and 21÷3 is 7

7 0
3 years ago
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
3 years ago
A shopkeeper has 2,625 markers. He would like to pack 25 markers in each box. How many boxes will he need?
Lerok [7]

Answer:

it's 105 boxes.

Step-by-step explanation:

hope this helps! and sorry for the person just trying to get points.

5 0
3 years ago
Percy delivers pizzas for pizza king. He is paid $6 an hour plus $2.50 for each pizza he delivers. Percy earned $280 last week.
Triss [41]
Hey You!

6 × 30 = 90

280 - 90 = 190

190 / 2.50 = 76

We can check using multiplication.

2.50 × 76 = 190

Percy delivered 76 pizzas.
7 0
3 years ago
Divide 120 in the ratio of 1:2
mestny [16]

Answer:

40:80

Step-by-step explanation:

x+2x=3x

3x=120

120/3=

40

40*2=80

40:80=1:2

6 0
3 years ago
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