Answer:
You can try emailing tech support and describing your issue. In order to get the best help as quickly as possible, try providing screenshots of what happens when you sign in or describe everything you see on the screen when the problem occurs, and quote error messages directly when possible.
Answer:
Moore’s law states that processor speeds, or overall processing power for computers will double every two years.
Explanation:
- Moore’s law is more than an observation than a law which was originated in 1970. The observation is about the number of transistors that is present in any system or an integrated system that will be doubled every couple of years.
- The real-world application of Moore's law can be seen during computing your business taxes, piloting a spaceship, or changing the television station, etc.
Attackers frequently use ACK scans to circumvent a firewall or other filtering tools. During a NULL scan, all packet flags are enabled. The most recent versions of Nessus Server and Client are compatible with Windows, Mac OS X, FreeBSD, and the vast majority of Linux variants.
<h3>What is ack scan ?</h3>
- ACK scans are used to identify hosts or ports that have been blocked or are resistant to other types of scanning. An attacker uses TCP ACK segments to learn about firewall or ACL configuration.
- Attackers probe our router or send unsolicited SYN, ACK, and FIN requests to specific UDP/TCP ports.
- TCP ACK Scan sends an ACK message to the target port to determine whether or not it is filtered.
- On unfiltered ports, a RST reply packet will be sent for both open and closed ports. Filtered ports will either generate no response or generate an ICMP reply packet with an unreachable destination.
- The TCP ACK scanning technique attempts to determine whether a port is filtered by using packets with the ACK flag set.
To learn more about ask scan refer to:
brainly.com/question/13055134
#SPJ4
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
Yes Microsoft and Apple used the closed-source approach to better secure from malware and make to make their operating systems more user friendly.
