Evaluate the expression for p = –1. –50p2 − 10p + 28 =

Mathematics

2 answers:

mars1129 [50]2 years ago

6 0

Answer:

-12

Step-by-step explanation:

$-50(-1)^2 -10(-1) + 28$
$-50(1) + 10 + 28$
$-50 + 38$
$-12$

Therefore, the answer is -12.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

LekaFEV [45]2 years ago

3 0

For p2 do you mean p multied by 2 or is it squared by 2

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Nat2105 [25]

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3 years ago

The function f(x) = x3 – 8x2 + x + 42 has zeros located at 7, –2, 3. Verify the zeros of f(x) and explain how you verified them.

xeze [42]

Answer:

zeros are {-2, 3, 7} as verified by graphing
end behavior: f(x) tends toward infinity with the same sign as x

Step-by-step explanation:

A graphing calculator makes finding or verifying the zeros of a polynomial function as simple as typing the function into the input box.

<h3>Zeros</h3>

The attachment shows the function zeros to be x ∈ {-2, 3, 7}, as required.

<h3>End behavior</h3>

The leading coefficient of this odd-degree polynomial is positive, so the value of f(x) tends toward infinity of the same sign as x when the magnitude of x tends toward infinity.

x → -∞; f(x) → -∞
x → ∞; f(x) → ∞

<em>Additional comment</em>

The function is entered in the graphing calculator input box in "Horner form," which is also a convenient form for hand-evaluation of the function.

We know the x^2 coefficient is the opposite of the sum of the zeros:

-(7 +(-2) +3) = -8 . . . . x^2 coefficient

And we know the constant is the opposite of the product of the zeros:

-(7)(-2)(3) = 42 . . . . . constant

These checks lend further confidence that the zeros are those given.

(The constant is the opposite of the product of zeros only for odd-degree polynomials. For even-degree polynomials. the constant is the product of zeros.)