First one m = .0666666
second one i don't know
third one is .1
Answer:
a) The expected number of smokers in a random sample of 140 students from this university is 16.8 smokers.
b) No, it is unlikely that smoking habits and waking up early to go to the gym on Saturday are independent.
Step-by-step explanation:
To calculate the expected numbers of smokers in a sample with size n=140 and proportion p=12%, we use the expected value of the binomial distribution:
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The expected number of smokers in a random sample of 140 students from this university is 16.8 smokers.
If we take a sample at the opening of the gym, the sample is not expected to be representative of the population of the students. Most of the students that go to the gym usually have healthy habits, so the proportions of smokers is expected to be lower than the average of the university population.
The answer is 160. U multiply all. PUT ME AS BEST
ok distribute the 6 by multiplying it by 1q and -5
5=6q-30-19
Now subtract 30-19
5=6q-11
add 11 to both sides
16=6q
divide both sides by 6
q= 16/6
simplify
16/2=8, 6/2=3
q=8/3
35 :) If you change the percent into a decimal (0.70) and multiply that by 50, you will get the answer!