Answer:
No solution or
(-3±
)/8
Step-by-step explanation:
To get the solution, move everything to the left side of the equation:
8x²+6x+5 = 0
If you try to factor the equation or graph it, you will see that it will never equal 0.
If you need an imaginary solution you can plug it into the quadratic equation:
-6±
over 16
Simplify and you get
-6±
over 16
-6±
over 16
Simplify the fraction and you can get
(-3±)/8
If you mean "factor over the rational numbers", then this cannot be factored.
Here's why:
The given expression is in the form ax^2+bx+c. We have
a = 3
b = 19
c = 15
Computing the discriminant gives us
d = b^2 - 4ac
d = 19^2 - 4*3*15
d = 181
Note how this discriminant d value is not a perfect square
This directly leads to the original expression not factorable
We can say that the quadratic is prime
If you were to use the quadratic formula, then you should find that the equation 3x^2+19x+15 = 0 leads to two different roots such that each root is not a rational number. This is another path to show that the original quadratic cannot be factored over the rational numbers.
H (x) = b - 9/x
At (-6 , 19) ,
h (x) = 19 , x = -6 ,
19 = b - (9/-6)
19 = b + 3/2
b = 35/2
The answer is C i believe
Answer:
y = 
x + 9
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = 
with (x₁, y₁ ) = (- 2, 6 ) and (x₂, y₂ ) = (2, 12 )
m = 
= 
= 
= , then
y = x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation.
Using (2, 12 ) , then
12 = 3 + c ⇒ c = 12 - 3 = 9
y = x + 9 ← equation of line
