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3 years ago

13

BONUS: In the kite shown below, the perimeter of the kite is 16 units.

2 answers:

Ahat [919]3 years ago

8 0

The answer should be -y + X

8090 [49]3 years ago

3 0

Answer:

6(2) -2(-5) Substitute the values given into the expression and multiply. 12+10 ... 1. 2x-(3-4y), when x = 5 and y=-3. 215)-(3-4(-3)). 10-(3+12). 10-15. 2. ... + (3 - 3 x + 1 +. 6-3x = 4x + 4. Bebetto. 2=7x -. - 4-2=34+12. - ý 2=2y+12. + ... y = 2x-1. Simplify. Subtract 2x from each side. Multiply both sides by -1. 2+3 m.

Step-by-step explanation:

If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = (A) 1 (B) 4/3 (C) 17/5 (D) ... Divide both sides by 3 to get: x + y = 4 ... 2*(x+2y = 5) equals 2x+4y=10 ... or subtracting one from the other and it likely happens 90% times that ... If a question involves a system of two equations, and we're asked to find the value of ONE

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The value, V (t), in dollars, of a stock t months after it is purchased is modeled by the following equation.

11Alexandr11 [23.1K]

Answer:

Step-by-step explanation: $V(t)= 42(1-e ^{1.5t} ) +36$ is given value in dollars of a stock in t months after it is purchased.

a) Substitute 1 for t

$V(1) = 42(1-e^{-1.5} )+36 \\=67.852\\=67.85$

V(12) = $V(1) = 42(1-e^{-1.5*12} )+36 \\=77.00$

b) Find derivative for V

$V'(t) = 42(-1.5) e^{-1.5t} )\\\\=-63e^{-1.5t}$

c) When V(t) = 75

$V(t)=75= 42(1-e ^{1.5t} ) +36\\1-e ^{1.5t=0.9286\\=-2.639$

d) As t tends to infinity, exponent being in negative t tends to 0

So V tends to 42(1-0)+36 = 78

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3 years ago

How many miles is it from Turtle Bay to Waialua Bay

lidiya [134]

12.9 miles or 27 minutes

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3 years ago

Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a red card

joja [24]

Answer: $\dfrac{3}{51}$

Step-by-step explanation:

Given : The total number of cards in a deck = 52

Number of red cards = 26

There are two types of red cards : diamond and heart.

Number of diamond cards = 13

The probability that the first card is a diamond :-

$\dfrac{13}{52}=\dfrac{1}{4}$

Since diamond is also a red card.

Now, the total cards left = 51

The number of red cards left = 12

The probability that the second card is a red card (without repetition) is given by :-

$\dfrac{12}{51}$

Now, the probability of choosing a red card for the second card drawn, if the first card, drawn without replacement, was a diamond :-

$\dfrac{1}{4}\times\dfrac{12}{51}=\dfrac{3}{51}$

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