Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
Answer:
2. Tom ran from his house to the bus stop and waited. He realised that he missed the bus so he walked home
Step-by-step explanation:
He ran to the bus stop so his distance from his home is far, then he waited so the distance did not change, and then he went back home so the distance to the house got smaller again.
The coordinate of point S from the giving coordinate point is (-8,4)
<h3>Midpoint of coordinates</h3>
The formula for calculating the midpoint of coordinate point is expressed as:
M(x,y) = {(x₁+x₂)/2, (y₁+y₂)/2}
Determine the measure of the coordinate S
-2 = 4+x₂/2
2(-2) = 4+x₂
x₂ = -4-4
x₂ = -8
Similarly
0 = -4+y₂/2
0(2) = -4+y₂
y₂ = 4
Hence the coordinate of point S from the giving coordinate point is (-8,4)
Learn more on midpoint here: brainly.com/question/5566419
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