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storchak [24]
3 years ago
8

There are 5 green skittles, 4 orange skittles, and 3 red Skittles in a bag. What is the probability of red Skittle, Not replacin

g it (eating it), then picking a green skittle?​
Mathematics
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:

3/12

Step-by-step explanation:

the entire bag has 12 skittles. there are only 3 red. This gives a fraction of red skittles/entire bag in order to get the probability. So this would be 3/12 in this most basic sense? I am not sure if you need to go further than this or not. Hope this helps!

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You can use the direction vector as the coefficients of x and y for a line through (0, 0) perpendicular to that direction: x + y = 0. (A common factor of 4 can be removed from the coefficients.)

Translating the line up 2 and right 9, so it goes through the given point, we get ...

... (x -9) +(y -2) = 0

or

... x + y = 11

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How to solve 0=4+n/5?
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Let's solve your equation step-by-step.
<span>0=<span>4+<span>n/5
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</span>Step 3: Subtract 4 from both sides.<span><span><span><span><span>1/5</span>n</span>+4</span>−4</span>=<span>0−4
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Assume that a sample is used to estimate a population proportion μ . Find the margin of error M.E. that corresponds to a sample
hichkok12 [17]

Answer:

MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\

Step-by-step explanation:

Since the sample size is quite large, we can use the z-distribution.

The margin of error is  given by

$ MoE = z_{\alpha/2}(\frac{s}{\sqrt{n} } ) $

Where n is the sample size, s is the sample standard deviation and z_{\alpha/2} is the z-score corresponding to a 90% confidence level.

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