Question

Let f(x)=x^2+2 and g(x)=1-3x. Find each function value: (fg)(-1)

Answer 1

Answer:

12

Step-by-step explanation:

$f(x)=x^2+2$

$g(x)=1-3x$

$(fg)(x)=f(x) \times g(x)$

$\implies (fg)(x)=(x^2+2)(1-3x)$

$(fg)(-1)=((-1)^2+2)(1-3(-1))$

$\implies (fg)(-1)=(1+2)(1+3)$

$\implies (fg)(-1)=12$

Extra:

If you were looking for f[g(-1)], then:

$f[g(-1)]=f(4)=4^2+2=18$