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3 years ago

Let f(x)=x^2+2 and g(x)=1-3x. Find each function value: (fg)(-1)

Mathematics

1 answer:

Verizon [17]3 years ago

6 0

Answer:

Step-by-step explanation:

$f(x)=x^2+2$

$g(x)=1-3x$

$(fg)(x)=f(x) \times g(x)$

$\implies (fg)(x)=(x^2+2)(1-3x)$

$(fg)(-1)=((-1)^2+2)(1-3(-1))$

$\implies (fg)(-1)=(1+2)(1+3)$

$\implies (fg)(-1)=12$

Extra:

If you were looking for f[g(-1)], then:

$f[g(-1)]=f(4)=4^2+2=18$

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3 years ago

Read 2 more answers

Functions f(x) and g(x) are shown:

Dennis_Churaev [7]

Answer:

Shifted right 6 units.

Step-by-step explanation:

$g$ can be written as a squared binomial since it is of the form:

$x^2+2ax+a^2$ which can be written as $(x+a)^2$ .

When comparing the expression to the trinomial just mentioned it should be noted that $a$ is -6. So $g$ can be written as: $g(x)=(x-6)^2$ .

Note: Vertex form of a quadratic is $y=a(x-h)^2+k$ where (h,k) is the vertex.

The vertex of the parent is (0,0) and the vertex of $g$ is (6,0). So the parent has shifted right 6 units to get to where $g$ is located.

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3 years ago

Identify the independent and dependent variables in the following situation: Julie notices that her plant grows one inch for eve

ivolga24 [154]

Determine the independent variable and dependent variable in the situation

The independent variable is the "amount of water the plant receives", and the dependent variable is the "height of the plant".

An independent variable is a the variable which causes a change.

A dependent variable is the result or effect of a change.

Therefore, the independent variable from the phenomena is "amount of water" and the dependent variable is the "height of the plant".

brainly.com/question/23700645

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3 years ago

Consider formula a to be v = startfraction 2 pi r over t endfraction and formula b to be v2 = gv = g startfraction m subscript c

mars1129 [50]

The tangential speed of the satellite above the Earth's surface is $7.588 * 10^{3} m/s$ .

<h3>What is Tangential speed?</h3>

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The object or circle moves with a constant linear speed at any point along the circle.
This is known as the tangential speed.
$v=wr\\v=\frac{2\pi r}{T}$

The tangential speed of a satellite at the given radius and time is calculated as follows:

$v=\frac{2\pi *(150*10^{3}+6371*10^{3} }{90*60} \\v=7.588*10^{3} m/s$

Therefore, the tangential speed of the satellite above the Earth's surface is $7.588 * 10^{3} m/s$ .

Know more about Tangential speed here:

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#SPJ4

The correct question is shown below:
Consider formula A to be v = and formula B to be v2 = G. Write the letter of the appropriate formula to use in each scenario. Determine the tangential speed of the moon given the mass of Earth and the distance from Earth to the moon. Determine the tangential speed of a satellite that takes 90 minutes to complete an orbit 150 km above Earth’s surface.

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2 years ago

i just confused on what the triangular prisms volume is. i think i’m doing it correctly but online says something different.

DanielleElmas [232]

Answer:

The answer for just the triangular prism's volume is 175 inches cubed.

If you need me to add how to find the volume of the rectangular prism, please comment that you also need this then.

Step-by-step explanation:

A triangular prism's volume is equal to the base area (which is a triangle) multiplied by the length of the prism.

So find the area of the triangle and multiply it by 10 inches in this case.

So they are going to try to confuse on the triangle here because of they give three measurements where one of them is unnecessary in the formula .5bh.

The b and h represent the base and height respectively. The base and height of a triangle when intersected form 90 degree angle.

So we are using the 5 inches and 7 inches for it's height and base respectively.

The 9 inches is unnecessary in the calculation.

The volume if the triangular prism is found by doing .5(7)(5) times 10. The answer is in inches cube since inches*inches*inches=inches cubed or in^3.

.5(7)(5)(10)

.5(10)(7)(5)

(5)(35)

175

The answer for just the triangular prism's volume is 175 inches cubed.

If you need me to add how to find the volume of the rectangular prism, please comment that you also need this then.

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3 years ago