The correct answer is B. 8<=l<=10. You can find this because we know the length is 2 feel more than the width, so when the length is provided, we can find the area. 8*6 is 48, which is the minimum area, and 10*8 is 80, which is the maximum area allowed.
Answer:
Part a) The lateral area is 
Part b) The area of the two bases together is 
Part c) The surface area is 
Step-by-step explanation:
we know that
The surface area of a right cylinder is equal to

where
LA is the lateral area
B is the area of the base of cylinder
we have


Part a) Find the lateral area
The lateral area is equal to

substitute the values


Part b) Find the area of the two bases together
The area of the base B is equal to

so
the area of the two bases together is

Part c) Find the surface area of the cylinder

we have


substitute

Answer:
121.875 if calculated so 121.875 if it shows it or less
Answer:
x = 2
Step-by-step explanation:



This question is so easy.
7.8+(3.5x6.8)-1.5
=7.8+23.8-1.5
=30.1