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2 years ago

Please answer correctly.

Mathematics

1 answer:

liubo4ka [24]2 years ago

6 0

Answer:

B, C, E

Step-by-step explanation:

The factor of the expression is negative hence all terms are negative.

<u>Equivalent expressions are:</u>

B, C, E

The rest have positive terms and therefore non-equivalent

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Giving 15 points for help!

kolezko [41]

Answer: The correct statements are 'The equation 2n = p should be 2p = n' , 'The actual cost of the onions is $3.00 per pound' and 'Potatoes cost $1.50 per pound.'

Step-by-step explanation:

Here, p represents cost of one potato and n represents the cost of one onion.

And, According to the question, He purchases 6 pounds of potatoes, p, and 3 pounds of onions, n, for $18.

Therefore, 6p +3n = 18 ------(1)

And, Onions cost twice as much as potatoes.

Therefore, n= 2p ---------(2)

Putting the values of n from 2) in equation 1),

we get, 6p+3(2p)=18

⇒6p+6p=18 ⇒ 12p =18 ⇒ p = 1.5 dollar.

Thus cost of one potato= $1.5

And cost of one onion = $ 2× 1.5= $ 3.00

Thus with help of above explanation we can say that Options first, third and fifth are correct.

8 0

3 years ago

Read 2 more answers

11 x minus 3 y = negative 17. Negative 4 x + 3 y = negative 18. Negative 7 x = negative 35 Negative 7 x = 35 7 x = negative 35 7

posledela

Answer:

7 x = -35

Step-by-step explanation:

Which equation results from adding the equations in this system? 11 x minus 3 y = -17. Negative 4 x + 3 y = - 18.

- 7 x = negative 35

- 7 x = 35

7 x = negative 35

7 x = 35

In this problem we need to add the equations below i.e.

11x-3y = -17 and -4x+3y=-18

Adding both equations,

11x-3y+(-4x)+3y = -17+(-18)

7x= -35

7 x = negative 35

Hence, the correct option is (c).

5 0

2 years ago

The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard

PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 8.59, \sigma = 0.63$