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stealth61 [152]
2 years ago
13

What are the values of a 1 and r of the geometric series? 1 3 9 27 81.

Mathematics
1 answer:
sp2606 [1]2 years ago
3 0

For the given geometric series the value of the common ratio(r) is 3, while the value of a₁  is 1.

<h3>What is geometric series?</h3>

A series of numbers whose any two consecutive numbers are always in a common ratio of that series.

Given to us

Series,  1 3 9 27 81

To find the value of the common ratio(r), we will simply find the ratio of any two consecutive numbers, therefore,

r = ratio = \dfrac{3}{1} = 3

As we can see the common ratio of the given series is 3, therefore, every next number will be thrice the number before.

We need to find the value of a₁ for the given  series, and as we know that a₁ is the first number of the series with which the series is starting, therefore,

a₁  = 1

Hence, for the given geometric series the value of the common ratio(r) is 3, while the value of a₁  is 1.

Learn More about Geometric Series:

brainly.com/question/14320920

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2x+4=256  subtract 4 from both sides

2x=252  divide both sides by 2

x=126
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Step-by-step explanation:

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xz_007 [3.2K]

Full Question:

Find the volume of the sphere. Either enter an exact answer in terms of π or use 3.14 for π and round your final answer to the nearest hundredth. with a radius of 10 cm

Answer:

The volume of the sphere is ⅓(4,000π) cm³ or 4186.67cm³

Step-by-step explanation:

Given

Solid Shape: Sphere

Radius = 10 cm

Required

Find the volume of the sphere

To calculate the volume of a sphere, the following formula is used.

V = ⅓(4πr³)

Where V represents the volume and r represents the radius of the sphere.

Given that r = 10cm,.all we need to do is substitute the value of r in the above formula.

V = ⅓(4πr³) becomes

V = ⅓(4π * 10³)

V = ⅓(4π * 10 * 10 * 10)

V = ⅓(4π * 1,000)

V = ⅓(4,000π)

The above is the value of volume of the sphere in terms of π.

Solving further to get the exact value of volume.

We have to substitute 3.14 for π.

This gives us

V = ⅓(4,000 * 3.14)

V = ⅓(12,560)

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V = 4186.67 ---- Approximated

Hence, the volume of the sphere is ⅓(4,000π) cm³ or 4186.67cm³

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