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2 years ago

What are the values of a 1 and r of the geometric series? 1 3 9 27 81.

Mathematics

1 answer:

sp2606 [1]2 years ago

3 0

For the given geometric series the value of the common ratio(r) is 3, while the value of a₁ is 1.

<h3>What is geometric series?</h3>

A series of numbers whose any two consecutive numbers are always in a common ratio of that series.

Given to us

Series, 1 3 9 27 81

To find the value of the common ratio(r), we will simply find the ratio of any two consecutive numbers, therefore,

$r = ratio = \dfrac{3}{1} = 3$

As we can see the common ratio of the given series is 3, therefore, every next number will be thrice the number before.

We need to find the value of a₁ for the given series, and as we know that a₁ is the first number of the series with which the series is starting, therefore,

a₁ = 1

Hence, for the given geometric series the value of the common ratio(r) is 3, while the value of a₁ is 1.

Learn More about Geometric Series:

brainly.com/question/14320920

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Frank writes his name in both French and English with chalk, pen, pencil and marker. How many different ways did he write his na

AlekseyPX

Answer:

Step-by-step explanation:

There are 4 possible ways he could have written it: chalk, pen, pencil, and marker.

There are 2 ways he wrote it: French and English

4*2=8

He wrote his name in 8 different ways.

5 0

3 years ago

What is 4.373 ×10^10 in standard notation

Lera25 [3.4K]

Your answer is:
43,730,000,000
Hope this helps!=)

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3 years ago

How do you solve this whole thing please?

NemiM [27]

Answer:

Step-by-step explanation:

Let's look at the first two, and hopefully you'll be able to figure the rest out:

1. Answer below

$d = rt$

The problem asks us to solve for $r$ , so that means we need to get $r$ on one side of the equation by itself. To do so, we will need to divide both sides of the equation by $t$ :

$\frac{d}{t} = \frac{rt}{t}$

$\frac{d}{t} = r$

2. Answer below

$B = T - Lc$

The problem asks us to solve for $T$ , so that means we need to get $T$ on one side of the equation by itself. To do so, we will need to add $Lc$ to both sides of equation:

$B + Lc = T - Lc + Lc$

$B + Lc = T$

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3 years ago

Consider the 1-to10^19 scale on which the disk of the Milky Way Galaxy fits on a football field. On this scale, how far is it fr

bezimeni [28]

Beautiful ! What a great exercise ! I won't even check to verify
that 1:10⁻¹⁹ is an appropriate scale to map the Milky Way onto a
football field. I'll just accept it and go from there.

(4.4 light years) x (10⁻¹⁹) = (2.5848 x 10¹³ miles) x (10⁻¹⁹)

   = 2.5848 x 10⁻⁶ mile

   = 0.164 inch .

(1,391,400 kilometers) x (10⁻¹⁹) = 1.3914 x 10⁻¹⁰ meter

Research Conclusions:

If the Milky Way shrinks to fit on a football field, then

-- Alpha Centauri is 0.164 inch from us.

-- The sun's diameter is about 1.39 times that of a Hydrogen atom.

Playing with this same fun concept a little more:

-- The Earth is sailing around in its orbit, once a year,
    about 0.000015 millimeter from the sun.

-- It takes light almost 27 years to travel 1 inch !

wow !

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3 years ago

Read 2 more answers

(2x + 3) (2x2 – 2+4)

nadya68 [22]

Answer:

(2x + 3) (2(2)x2 – 2+4)

Step-by-step explanation:

thats what i got hope it helps :)

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3 years ago

Read 2 more answers