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aleksandr82 [10.1K]

3 years ago

6

PLEASE HELP ME VERIFY THE IDENTITY!! I have been stuck on this question forever!

1 answer:

Morgarella [4.7K]3 years ago

7 0

Step-by-step explanation:

$\frac{1 + \cot(x) }{ \cos(x) } - \csc(x) = \sec(x)$

$\frac{1}{ \cos(x) } + \frac{ \cot(x) }{ \cos(x) } - \csc(x) = \sec(x)$

$\sec(x) + \frac{1}{ \sin(x) } - \csc(x) = \sec(x)$

$\sec(x) + \csc(x) - \csc(x) = \sec(x)$

$\sec(x) = \sec(x)$

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Marshals mother buys two boxes of chlorine bars each week each box contains eight glory bars and continues to buy two boxes each

Lisa [10]

Answer:

832

Step-by-step explanation:

there's 52 weeks in a year

52 x 2 = 104

104 x 8 = 832

hope this helps.

5 0

3 years ago

Convert the number in scientific notation to standard notation.<br> <img src="https://tex.z-dn.net/?f=1.8%20%2A%2010%5E6" id="Te

Keith_Richards [23]

The answer is 1000001.8

5 0

3 years ago

Match each differential equation to a function which is a solution.

inessss [21]

Answer: 1 - C

2 - E

3 - no answer

4 - B

Step-by-step explanation:

A. $y = 3x+x^2$

$y' = 3 + 2x\\y'' = 2$

Replace in 1:

$y'' + y = 0$

$2 + 3x + x^2 \neq 0$

So, A is not an answer for 1

Replace in 2:

$y' = 3y$

$3+2x = 3(3x + x^2)$

So, A is not an answer for 2

Replace in 3

$2x^2y'' + 3xy'= y$

$2x^2(2) + 3x(3 + 2x) = 4x^2 + 9x + 6x^2 \neq 3x+x^2$

So, A is not an answer for 3

Replace in 4

$y'' + 6y' + 8y = 0$

$2 + 6(3+2x)+8(3x + x^2) = 2+18+12x+24x+8x^2 \neq 0$

So, A is not an answer for 4

B. $y = e^{-4x}$

$y' = -4e^{-4x}$

$y'' = 16e^{-4x}$

Replace in 1

$y'' + y = 0$

$16e^{-4x} -4e^{-4x} = 12e^{-4x} \neq 0$

So, B is not an answer for 1

Replace in 2

$y' = 3y$

$-4e^{-4x} \neq 3e^{-4x}$

So, B is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(16e^{-4x}) +3x(-4e^{-4x}) \neq e^{-4x}$

So, B is not an answer for 3

Replace in 4

$y'' + 6y' +8y = 0$

$16e^{-4x} + 6(-4e^{-4x}) + 8e^{-4x} = e^{-4x}(16-24+8) = 0$

So, B is an answer for 4

C. $y = sin(x)$

$y' = cos(x)$

$y'' = -sin(x)$

Replace in 1

$y'' + y = 0$

$-sin(x) + sin(x) = 0$

So, C is an answer for 1

We jump to

D. $y = x^{12}$

$y' = 12x^{11}$

$y'' = 132 x^{10}$

Replace in 2

$y' = 3y$

$12x^{11} \neq 3x^{12}$

So, D is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(132x^{10}) + 3x(12x^{11}) = 300x^{12} \neq x^{12}$

So, D is not an answer for 3

E. $y = 6e^{3x}$

$y' = 18e^{3x}$

$y'' = 54e^{3x}$

Replace in 2

$y' = 3y$

$18e^{3x} = 3(6e^{3x}) = 18e^{3x}$

So, E is an answer for 2

3 0

3 years ago

If f (x) = startroot one-half x minus 10 endroot 3, which inequality can be used to find the domain of f(x)? startroot one-half

tankabanditka [31]

A function assigns values. The inequality one-half x minus 10 greater-than-or-equal-to 0 should be satisfied.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The domain of a function is a set of values for which the equation is satisfied. Since the function has under root values, the value which is under the root should be non-negative so that it does not give a complex number, therefore,

The inequality $\sqrt{\dfrac12x^2-10}\geq 0$ satisfied to find the domain of the function f(x).

Also, we can write that 0.5x²-10≥0 for the value to be positive.

Hence, the inequality one-half x minus 10 greater-than-or-equal-to 0 should be satisfied.

Learn more about Function:

brainly.com/question/5245372

6 0

2 years ago

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Vedmedyk [2.9K]

Answer:

30

Step-by-step explanation:

How much was the decrease from Figure A to Figure B (let x be the decrease): 45x = 27
Divide each by 45 to cancel out the 45 next to x. It should now look like this: x = 3/5
To find x, we would normally multiply x by 3/5, but because we don't have x, we just DIVIDE 18 by 3/5: 18 ÷ 3/5 = 30
So, x = 30

I hope this helps!

7 0

3 years ago