We are given that the note A5 has a frequency of 880 Hz. We are asked what for the frequency of A7 and two octaves above A5.
For A7, referring to the frequency table of notes, its frequency is 3520 Hz.
Two octaves above A5 is A3. The frequency of this note is 220 Hz.
Answer:
24 + 8i
Step-by-step explanation:
t = 4
u = 6 + 2i
t x u
= 4 ( 6 + 2i )
= 24 + 8i
Answer:
(a) 20.9%
(b) 60.8%
(c) 6.3%
Step-by-step explanation:
Use binomial probability.
P = nCr pʳ qⁿ⁻ʳ
(a)
P = ₁₀C₅ (0.59)⁵ (1−0.59)¹⁰⁻⁵
P = 0.209
(b)
P = ₁₀C₆ (0.59)⁶ (1−0.59)¹⁰⁻⁶
+ ₁₀C₇ (0.59)⁷ (1−0.59)¹⁰⁻⁷
+ ₁₀C₈ (0.59)⁸ (1−0.59)¹⁰⁻⁸
+ ₁₀C₉ (0.59)⁹ (1−0.59)¹⁰⁻⁹
+ ₁₀C₁₀ (0.59)¹⁰ (1−0.59)¹⁰⁻¹⁰
P = 0.608
(c)
P = ₁₀C₀ (0.59)⁰ (1−0.59)¹⁰⁻⁰
+ ₁₀C₁ (0.59)¹ (1−0.59)¹⁰⁻¹
+ ₁₀C₂ (0.59)² (1−0.59)¹⁰⁻²
+ ₁₀C₃ (0.59)³ (1−0.59)¹⁰⁻³
P = 0.063
This is a TRUE statement. Consider the following example:
5 can also be written as
. Any variable raised to power 0 is equal to 1. So x raised to power 0 is equivalent to multiplying by 1, it leaves the expression/number unchanged.
So yes, polynomial of degree zero is a constant term
Answer:
sin(2x)=cos(π2−2x)
So:
cos(π2−2x)=cos(3x)
Now we know that cos(x)=cos(±x) because cosine is an even function. So we see that
(π2−2x)=±3x
i)
π2=5x
x=π10
ii)
π2=−x
x=−π2
Similarly, sin(2x)=sin(2x−2π)=cos(π2−2x−2π)
So we see that
(π2−2x−2π)=±3x
iii)
π2−2π=5x
x=−310π
iv)
π2−2π=−x
x=2π−π2=32π
Finally, we note that the solutions must repeat every 2π because the original functions each repeat every 2π. (The sine function has period π so it has completed exactly two periods over an interval of length 2π. The cosine has period 23π so it has completed exactly three periods over an interval of length 2π. Hence, both functions repeat every 2π2π2π so every solution will repeat every 2π.)
So we get ∀n∈N
i) x=π10+2πn
ii) x=−π2+2πn
iii) x=−310π+2πn
(Note that solution (iv) is redundant since 32π+2πn=−π2+2π(n+1).)
So we conclude that there are really three solutions and then the periodic extensions of those three solutions.
5.8K views
View upvotes
5
Related Questions (More Answers Below)
