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2 years ago

An equation of the circle with center (h, k) and radius r is (−ℎ)^2+(−)^2=^2

Mathematics

1 answer:

Verdich [7]2 years ago

4 0

Answer:

An equation of the circle with center (h, k) and radius r:

$(x-h)^2+(y-k)^2=r^2$

Step-by-step explanation:

Not sure what you need to find out but,

An equation of the circle with center (h, k) and radius r:

$(x-h)^2+(y-k)^2=r^2$

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PLS HELP

DochEvi [55]

Answer:

10.5

Step-by-step explanation:

v=158

l×w×h =158

l×5×3=158

l×15=158

L =158÷15=10.5

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3 years ago

What is the solution of the system of equations graphed below?

Dahasolnce [82]

Answer: B

Step-by-step explanation: Look at where the lines intersect

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3 years ago

What is 8 1/3 x 3/5?

Savatey [412]

$8\frac{1}{3}\times\frac{3}{5}=\frac{8\times3+1}{\not3_1}\times\frac{\not3^1}{5}=\frac{24+1}{1}\times\frac{1}{5}=\frac{25}{1}\times\frac{1}{5}=\frac{25}{5}=\boxed5$

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4 years ago

Triangle NMO has vertices at N(−5, 2), M(−2, 1), O(−3 , 3). Determine the vertices of image N′M′O′ if the preimage is reflected

Firdavs [7]

Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below

$\begin{gathered} y\rightarrow y \\ x\rightarrow2a+x \\ where \\ x=a\rightarrow\text{ vertical line} \end{gathered}$

Hence, in our case

$\Rightarrow(x,y)=(2*-4-x,y)=(-8-x,y)$

Transform points N, M, and O accordingly,

$\begin{gathered} \Rightarrow N^{\prime}=(-8-(-5),2)=(-8+5,2)=(-3,2) \\ \Rightarrow M^{\prime}=(-8-(-2),1)=(-6,1) \\ \Rightarrow O^{\prime}=(-8-(-3),3)=(-5,3) \end{gathered}$ <h2>Therefore, the answer is the first option (top to bottom)</h2>

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1 year ago

An office uses 478 pounds of paper in one week. The paper comes in packages that hold 18 pounds of paper each. How many packages

ddd [48]

To solve this, you would divide 478 by 18, which equals 26.5555556. Since you can't have half a package of paper, the answer would be 26. Hope this helps!

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3 years ago