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mel-nik [20]
3 years ago
6

A triangle pyramid with a based length of 9 inches a base height of 10 inches and Height of 32 inches

Mathematics
1 answer:
Naily [24]3 years ago
7 0
Sorry what is the thing to times 9 by 10 by 32 sorry i don't think you have all the question here
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((write an equation using y=mx+b format))
butalik [34]

Answer: y = 2x + 5

Step-by-step explanation:

8 0
3 years ago
What is the value of y?
Gelneren [198K]

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Step-by-step explanation:

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2 years ago
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If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
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Answer:

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Step-by-step explanation:

18/3=6

30/5=6

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2 years ago
Which is the graph of g(x)?
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Answer:

the answer is letter D

Step-by-step explanation:

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2 years ago
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