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Gnoma [55]
3 years ago
7

A shoreline observation post is located on a cliff such that the observer is 280 feet above sea level. The observer spots a ship

approaching the shore and the ship is traveling at a constant speed.
Requried:
a. When the observer initially spots the ship, the angle of depression for the observer's vision is 6 degrees. At this point in time, how far is the ship from the shore?
b. After watching the ship for 43 seconds, the angle of depression for the observer's vision is 16 degrees. At this point in time, how far is the ship from the shore?
Mathematics
1 answer:
morpeh [17]3 years ago
4 0

Answer:

Step-by-step explanation:

a) D/280 = tan(90 - 6)

   D = 280tan84 = 2,664 ft

b) D/280 = tan(90 - 16)

   D = 280tan74 = 976 ft

ship speed = (2664 - 976) / 43 = 39.2 ft/s

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vaieri [72.5K]

Answer:

It's A. 28 degrees

Step-by-step explanation:

First, you determine the angle measure directly below x. That is a straight line, so it measures 180 degrees. You can add 38 and 90 degrees, and then subtract from 180 to get the last angle measure. This gives you 52. The right 3 angles measure 90 degrees, because they are on the opposite side of a right angle marker. You can add 10 and 52 and then subtract from 90 to get the missing x value, 28.

6 0
3 years ago
A states division of motor vehicles claims that 60% of teens pass their drivers test on the first attempt. an investigative repo
____ [38]

Answer: There is convincing evidence at the  the significance level that the DMV's claim is incorrect.

Step-by-step explanation:

Since we have given that

Hypothesis:

H_0:p=0.6\\\\H_a:p\neq 0.6

Probability of teens pass their drivers test on the first attempt = 60% = 0.60

Number of teens = 125

Number of them passed the tests on their first try = 86

\hat{p}=\dfrac{86}{125}=0.688

So, the value of test statistic would be

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.688-0.60}{\sqrt{\dfrac{0.6\times 0.4}{125}}}\\\\z=\dfrac{0.088}{0.0438}\\\\z=2.009\\\\z\approx 2.01

At α = 0.05% level of significance, critical value = 1.645

Since 1.645 < 2.01

So, we will reject the null hypothesis.

Hence, there is convincing evidence at the  the significance level that the DMV's claim is incorrect.

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