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Kisachek [45]
4 years ago
10

How many commuters must be randomly selected to estimate the mean driving time of chicago commuters? we want 95% confidence that

the samoke mean is within 4 minutes of the population mean, and the population standard deviation is known to be 10 minutes?
Mathematics
1 answer:
Anna71 [15]4 years ago
4 0
Margin of error is calculated using the following formula:

Margin error = Z-value*SD/Sqrt (N)

Where: Z -value at 95% confidence = 1.96; SD = Standard deviation = 10 minutes; N = Sample size; Margin error = 4 minutes

Substituting;
4 = 1.96*10/Sqrt (N)
Sqrt (N) = (1.96*10)/4 = 4.9
N = 4.9^2 = 24.01 ≈ 25

Therefore, 25 commuters will be selected at random to yield these results.
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4 years ago
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5 0
3 years ago
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Using the image below, where would the coordinates of point A be if the triangle was translated by ⟨x−4,y+3⟩?
Dennis_Churaev [7]

Answer:

(-9,4)

Step-by-step explanation:

so we are going to take the original coordinates (-5,1) and to the operation that the question wants us to do (x-4,y+3) by subsitituing the variables in so we get (-5-4,1+3)

Answer: (-9,4)

6 0
2 years ago
The circumference of the great wheel was twelve thousand and forty-one thousand inches. The cricumference of the lesser wheel wa
Korvikt [17]

Answer:

The larger wheel is 10979.04098 more than the smaller wheel.

Step-by-step explanation:

Given that,

The circumference of the great wheel was twelve thousand and forty-one thousandth inches.

C = 12000.041 inches

The circumference of the lesser wheel was only one thousand twenty-one and two hundred-thousand inches.

C' = 1021.00002 inches

We need to find how much larger was the great wheel. To find it, take the difference of C and C'.

C-C' = 12000.041 inches - 1021.00002 inches

= 10979.04098 inches

Hence, the larger wheel is 10979.04098 more than the smaller wheel.

5 0
3 years ago
Locate the absolute extrema of the function on the closed interval:<br> y = 3x^(2/3) - 2x, [-1, 1]
Alecsey [184]
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
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Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
7 0
3 years ago
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