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3 years ago

Point P is plotted on the coordinate grid. If point S is 10 units to the left of point P, what are the coordinates of point S?

Mathematics

1 answer:

Ket [755]3 years ago

4 0

Answer:

I can't really give an answer but I can describe how to get the answer

Step-by-step explanation:

First, we need the corrdinates of Point P which should be an answer of (x,y). After we got the coordinates, move 10 lines towards the left and replace the x with the number you have gotten by doing that and then you should get your answer (hopefully)

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Find the inverse Laplace transforms, as a function of x, of the following functions:

inn [45]

Answer: The required answer is

$f(x)=e^x+\cos x+\sin x.$

Step-by-step explanation: We are given to find the inverse Laplace transform of the following function as a function of x :

$F(s)=\dfrac{2s^2}{(s-1)(s^2+1)}.$

We will be using the following formulas of inverse Laplace transform :

$(i)~L^{-1}\{\dfrac{1}{s-a}\}=e^{ax},\\\\\\(ii)~L^{-1}\{\dfrac{s}{s^2+a^2}\}=\cos ax,\\\\\\(iii)~L^{-1}\{\dfrac{1}{s^2+a^2}\}=\dfrac{1}{a}\sin ax.$

By partial fractions, we have

$\dfrac{s^2}{(s-1)(s^2+1)}=\dfrac{A}{s-1}+\dfrac{Bs+C}{s^2+1},$

where A, B and C are constants.

Multiplying both sides of the above equation by the denominator of the left hand side, we get

$2s^2=A(s^2+1)+(Bs+C)(s-1).$

If s = 1, we get

$2\times 1=A(1+1)\\\\\Rightarrow A=1.$

Also,

$2s^2=A(s^2+1)+(Bs^2-Bs+Cs-C)\\\\\Rightarrow 2s^2=(A+B)s^2+(-B+C)s+(A-C).$

Comparing the coefficients of x² and 1, we get

$A+B=2\\\\\Rightarrow B=2-1=1,\\\\\\A-C=0\\\\\Rightarrow C=A=1.$

So, we can write

$\dfrac{2s^2}{(s-1)(s^2+1)}=\dfrac{1}{s-1}+\dfrac{s+1}{s^2+1}\\\\\\\Rightarrow \dfrac{2s^2}{(s-1)(s^2+1)}=\dfrac{1}{s-1}+\dfrac{s}{s^2+1}+\dfrac{1}{s^2+1}.$

Taking inverse Laplace transform on both sides of the above, we get

$L^{-1}\{\dfrac{2s^2}{(s-1)(s^2+1)}\}=L^{-1}\{\dfrac{1}{s-1}\}+L^{-1}\{\dfrac{s}{s^2+1}+\dfrac{1}{s^2+1}\}\\\\\\\Rightarrow f(x)=e^{1\times x}+\cos (1\times x)+\dfrac{1}{1}\sin(1\times x)\\\\\\\Rightarrow f(x)=e^x+\cos x+\sin x.$

Thus, the required answer is

$f(x)=e^x+\cos x+\sin x.$

4 0

4 years ago

Suppose that PR=47. Solve for x and find the lengths of PQ, and QR.

lidiya [134]

Answer:

x = 10

PQ = 27

QR = 20

Step-by-step explanation:

You can add up PQ and QR and set it equal to PR. Solve for x.

(2x + 7) + (2x) = 47

2x + 7 + 2x = 47

4x + 7 = 47

(4x + 7) - 7 = 47 - 7

4x = 40

4x/4 = 40/4

x = 10

Now, use the solved x-value to find PQ and QR.

PQ = 2x + 7

PQ = 2(10) + 7

PQ = 20 + 7

PQ = 27

QR = 2x

QR = 2(10)

QR = 20

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