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avanturin [10]
3 years ago
5

Simplify: 213(5) + 1111(5)

Mathematics
1 answer:
defon3 years ago
6 0

[Hello,BrainlyUser]

Answer:

6620

Step-by-step explanation:

213(5) + 1111 (5)=

Let's Multiply first.

213 × 5 = 1065

Then 1111 × 5 = 5555

5555 + 1065 = 6620

[CloudBreeze]

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Suppose that $50,000 from a retirement account is invested in a large-cap stock fund. After 20 yr, the value is $175,222.57. Use
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3 years ago
The temperature is -3°F at 7:00 A.M. During the next 4 hours, the temperature increases 21°F. What is the temperature at 11:00 A
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4 years ago
A substance abuse researcher wants to know whether reaction time is decreased by frequent alcohol use. He randomly selects 164 a
ella [17]

Answer:

We conclude that the reaction time is increased or remains same by frequent alcohol use.

Step-by-step explanation:

We are given that a substance abuse researcher wants to know whether reaction time is decreased by frequent alcohol use. He randomly selects 164 alcoholics and finds that their mean reaction time (in ms) to a stimulus equals 283.

Reaction times to the stimulus in the general population are distributed normally with a mean equal to 281 and a standard deviation equal to 28.

<u><em>Let </em></u>\mu<u><em> = mean reaction time after alcohol use.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 281      {means that the reaction time is increased or remains same by frequent alcohol use}

Alternate Hypothesis, H_A : \mu < 281      {means that the reaction time is decreased by frequent alcohol use}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}  ~ N(0,1)

where, \bar X = sample mean reaction time (in ms) = 283

            \sigma = population standard deviation = 28

            n = sample of alcoholics = 164

So, <u><em>test statistics</em></u>  =  \frac{283-281}{\frac{28}{\sqrt{164}}}  

                              =  0.915

The value of z test statistics is 0.915.

<em>Now, at 0.01 significance level the z table gives critical value of -2.3263 for left-tailed test.</em><em> Since our test statistics is more than the critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the reaction time is increased or remains same by frequent alcohol use.

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3 years ago
The L.C.M of 2and 4 is what?​
Anna35 [415]
It is 4



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4 0
2 years ago
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Answer:

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Step-by-step explanation:

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