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olasank [31]
2 years ago
11

14. This week, Anita spent 3 1/2 h practicing the piano. She also spent 6 1/4 h at soccer practice and 4 1/3 h on the telephone.

a) How much time, in total, did Anita spend on the piano and at soccer? b) How much more time did Anita spend at soccer than on the phone?
this is fractions
Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
7 0

Answer:  a)9 3/4 hours

B)1 11/12 hour

Step-by-step explanation:

Piano: 3 1/2 hour; 3hours 30min

Soccer: 6 1/4 hour; 6hours and 15 min

Telephone: 4 1/3 hour; 4 hours and 20 min.

Remember that in an hour there is 60 min, and 1/2 of an hour is 30 (min), 1/4  is 15(min) and 1/3 is 20(min).

a) 3hours and 30min + 6hours and 15 min

That gives us 9 hours and 45 min, which is 9 3/4 hours.

B) 6hours and 15 min — 4 hours and 20 min

That gives us 1 hour and 55 min, which is 1 11/12 hours.

I hope this helps you!

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Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Area = 128

Let the dimension of the paper be x and y;

Such that:

Length = x

Width = y

So:

Area = x * y

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128 = x * y

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When 1 inch margin is at top and bottom

The length becomes:

Length = x + 1 + 1

Length = x + 2

When 2 inch margin is at both sides

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Substitute \frac{128}{y} for x

A = (\frac{128}{y} + 2) * (y + 4)

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A = 128 + \frac{512}{y} + 2y + 8

Collect Like Terms

A = \frac{512}{y} + 2y + 8+128

A = \frac{512}{y} + 2y + 136

A= 512y^{-1} + 2y + 136

To calculate the smallest possible value of y, we have to apply calculus.

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This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

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