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Bess [88]
4 years ago
9

Diameter of sphere is 8cm it is beaten and drawn out to a diameter of 2 mm find length of wire

Mathematics
1 answer:
m_a_m_a [10]4 years ago
4 0
<span>Diameter of the sphere = 8 cm. Therefore, the radius of the sphere = 8/2 = 4 cm Volume of the sphere = 4/3 * 22/7 * 3 * 3 * 3 cu. cm. The sphere is beaten and drawn into a wire, the wire is cylinder of the diameter = 0.2 cm Area of the base of the cylinder = pi * r2 = 22/7 * 0.2 * 0.2 sq. cm volume of the wire = pi * r2 * I = 22/7 * 0.2 * 0.2 * 1 Therefore, 22/7 * 0.2 * 0.2 * I = 4/3 * 22/7 * 4 * 4 * 4 Therefore I = 4/3 * 22/7 * 4 * 4 * 4 * 7/22 * 1/0.04 I = 256/3 * 1/0.04 I = 2113 cm</span>
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<h2><u><em>Answer is 8/9</em></u></h2>
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3 years ago
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ANTONII [103]

The addition of the polynomial x^{3}+3xy-2xy^{2} +y^{3} with 2x^{3}-5x^{2} y-3xy^{2}-2y^{3} is  3x^{3}+3xy-5x^{2} y-5xy^{2}-y^{3}.

What is a polynomial?

⇒ A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.

⇒ In the addition of polynomials, the like terms are added while in subtraction, the like terms are subtracted.

Calculation;

We have been given two polynomial which we have to add   x^{3}+3xy-2xy^{2} +y^{3} and 2x^{3}-5x^{2} y-3xy^{2}-2y^{3}

The sign after addition or subtraction will always be of the variable having more value.

(x^{3}+3xy-2xy^{2} +y^{3} )+(2x^{3}-5x^{2} y-3xy^{2}-2y^{3})

On adding like terms with each other

⇒ (x^{3} +2x^{3})+ 3xy-5x^{2} y-(2xy^{2}+3xy^{2})+(y^{3}-2x^{3})

⇒ 3x^{3}+3xy-5x^{2} y-5xy^{2}-y^{3}

Hence the addition of the polynomialx^{3}+3xy-2xy^{2} +y^{3} and 2x^{3}-5x^{2} y-3xy^{2}-2y^{3} is 3x^{3}+3xy-5x^{2} y-5xy^{2}-y^{3}.

Learn more about polynomial here :

brainly.com/question/1487158

#SPJ9

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