Answer:

Explanation:
by solving it we get,
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<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:depends on the college but generally 32-36 also depends on what your studying
Explanation:
Using the z-distribution, it is found that the smallest sample size required to obtain the desired margin of error is of 4330.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
The margin of error is given by:

In this problem:
- The estimate of the proportion is of
.
- The desired margin of error is of M = 0.01.
- 90% confidence level, hence
, z is the value of Z that has a p-value of
, so
.
Then, we solve for n to find the minimum sample size.






Rounding up, the smallest sample size required to obtain the desired margin of error is of 4330.
To learn more about the z-distribution, you can take a look at brainly.com/question/12517818
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