HELPPPPPPPPPPPPPPPPP

Please EXPLAIN how to get this answer so I can do it with other problems. A straight answer would be great, but I have to do abo

OLEGan [10]

Answer:

PQ = 3.58, and RQ = 10.4

Step-by-step explanation:

We are given the hypotenuse of the triangle, and an angle. Use sin and cos to solve.

Hypotenuse = 11,

Opposite side is PQ

Adjacent side is RQ

x = 19

Sin x = (opposite side)/(hypotenuse)

Cos x = (adjacent side)/(hypotenuse)

For PQ, this is the side opposite to the angle, so use sin,

Sin 19 = x/11

11(Sin 19) = x

3.58 = x (rounded to the nearest hundredth)

For RQ, this is the side adjacent to the angle, so use cos,

Cos 19 = x/11

11(Cos 19) = x

10.4 = x (rounded to the nearest hundredth)

6 0

2 years ago

Arachnophobia is the fear of spiders. People with arachnophobia suffer to different degrees, but they tend to react intensely to

zepelin [54]

Answer:

1. The null hypothesis is that there is no difference between the population means (in other words, there is no treatment effect).

2. The<u> alternative hypothesis</u> is that at least one of the population means is different from another (in other words, there is an effect Of at least one Of the treatments).

Step-by-step explanation:

In a statistical analysis, the statistician shares his participants into several groups and administers treatments to them. After administering the treatment, he might want to compare the values obtained to see if there is a difference. If he accepts the null hypothesis as true, that means that there was no difference between the population means. This can also be taken to mean that the result had no difference among the groups.

But if the alternative hypothesis was true, that means that the population means were not all equal and so, there was an effect from the treatment administered.

7 0

2 years ago

2. Helen can type 120 words in 4 minutes. How many words can she type

erastovalidia [21]

Answer:

The Answer is 180 words

6 0

2 years ago

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Exercise 3.5. For each of the following functions determine the inverse image of T = {x ∈ R : 0 ≤ [x^2 − 25}.

masya89 [10]

a. The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

b. The inverse image of g(x) is $g^{-1}(x) = e^{x}$

c. The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

<h3 /><h3>The domain of T</h3>

Since T = {x ∈ R : 0 ≤ [x^2 − 25} ⇒ x² - 25 ≥ 0

⇒ x² ≥ 25

⇒ x ≥ ±5

⇒ -5 ≤ x ≤ 5.

<h3>Inverse image of f(x)</h3>

The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

f : R → R defined by f(x) = 3x³

Let f(x) = y.

So, y = 3x³

Dividing through by 3, we have

y/3 = x³

Taking cube root of both sides, we have

x = ∛(y/3)

Replacing y with x we have

y = ∛(x/3)

Replacing y with f⁻¹(x), we have

So, the inverse image of f(x) is f⁻¹(x) = ∛(x/3)

<h3>Inverse image of g(x)</h3>

The inverse image of g(x) is $g^{-1}(x) = e^{x}$

g : R+ → R defined by g(x) = ln(x).

Let g(x) = y

y = ln(x)

Taking exponents of both sides, we have

$e^{y} = e^{lnx} \\e^{y} = x$

Replacing x with y, we have

$y = e^{x}$

Replacing y with g⁻¹(x), we have

So, the inverse image of g(x) is $g^{-1}(x) = e^{x}$

<h3>Inverse image of h(x)</h3>

The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

h : R → R defined by h(x) = x − 9

Let y = h(x)

y = x - 9

Adding 9 to both sides, we have

y + 9 = x

Replacing x with y, we have

x + 9 = y

Replacing y with h⁻¹(x), we have

So, the inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

Learn more about inverse image of a function here:

brainly.com/question/9028678

5 0

1 year ago

Emily is enering a bicycle race for charity... Her mother pledges $0.40 for every 0.25 mile she bikes........ if Emily bikes 15

Paul [167]

Answer:

$16, sorry if its wrong (im pretty sure i'm right tho)

6 0

2 years ago

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