Answer: i'd say c
Step-by-step explanation:
Answer:
B = 4
T = 2
Step-by-step explanation:
First, figure out the equation.
We know that bicycles have 2 wheels, that there are 3 on a tricycle, and there are a total of 14 wheels and a total of 6 bicycles and tricycles.
Let b stand for bicycles and t stand for tricycles:
14 = 2b + 3t
6 = b + t
We can figure out the amount of either by rearranging the second equation to isolate one variable. I will solve it in two ways
In the first way, I will solve for b
(-t) 6 = b + t (-t)
6 - t = b
Plug this into the first equation and solve for remaining variable
14 = 2(6 - t) +3t
14 = 12 - 2t + 3t
14 = 12 +t
-12 -12
2 = t
6 - 2 = b
b = 4
The second way was to solve for t first
(-b) 6 = b + t (-b)
6 - b = t
14 = 2b + 3(6 - b)
14 = 2b + 18 - 3b
(-18) 14 = 18 -b (-18)
-4/-1 = -b/-1
b = 4
6 - 4 = t
t = 2
It doesn't matter which way you go, they both give you the exact same answer.
Sooo, recap!
1) write equations
2) switch the easier of the two to isolate one variable
3) substitute to find other variable (x2)
4) Find answers! =D
Hope this helps!
Answer:
D
Step-by-step explanation:
But basically, one by one you try moving the terms out of the radical.
75 is also 25 * 3 and since 25 has a perfect square root of 5 that goes out and 3 stays inside the radical.
x^3 is also x^2 * x and since x^2 has a perfect square root which is just x that goes outside while the remaining x stays inside.
y^9 is also y^8 * y and since we move variables out the radical in twos y^ goes outside the radical and y stays inside alone.
Finally, z is just z it can't be taken out so it stays inside the radical.
Hope that helps!
N=number of nickels
d=number of dimes
q=number of quarters
example
if n:d=3:8
lets say n=3 and d=8
3*8=8*3
so
8n=3d
slightly confusing but go with it, it migh make sense or it might not
n:d=3:8
8n=3d
d:q=4:5
5d=4q
solve for one of them
solve for nickels in first and quarters in second
8n=3d, n=(3/8)d
5d=4q, (4/5)d=q
5n+10d+25q=690
divide by 5 to make it easeir
n+2d+4q=138
sub (3/8)d for n
sub (4/5)d for q
(3/8)d+2d+5(5/4)d=138
(3/8)d+2d+25/4d=138
3/8+2+25/4=
3/8+16/2+50/8=
69/8
(69/8)d=138
times both sides by 8
69d=1104
divide both sides by 69
d=16
16 dimes
sub back
(5/4)d=q
(5/4)16=q
80/4=q
20=q
(3/8)d=n
(3/8)16=n
48/8=n
6=n
6 nickles
16 dimes
20 quarters
yah
