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2 years ago

Which equation shows a valid, practical step in solving, Someone please help

Mathematics

2 answers:

IRISSAK [1]2 years ago

8 0

Answer:

Answer: Is third one

hope it help you

Thank u

n200080 [17]2 years ago

3 0

Answer:

D. (∜(2x-8)^4=(-∜(2x+8)^4

Step-by-step explanation:

∜(2x-8)+∜(2x+8)=0

Rearrange the radical on the left side of the equation

∜(2x-8)=-∜(2x+8)

Raise both sides to the 4 power

(∜(2x-8))^4=(-∜(2x+8))^4

Determine the sign for exponential or radical expressions

(∜(2x-8))^4=(∜(2x+8))^4

Simplify the radical expression

2x-8=(∜(2x+8))^4

Simplify the radical expression

2x-8=2x+8

Rearrange variables to the left side of the equation

2x-2x=8+8

Apply the Inverse Property of Addition

0=8+8

Simplify

0=16

No solution

The step that makes the most sense is D. (∜(2x-8)^4=(-∜(2x+8)^4

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Given limit f(x) = 4 as x approaches 0. What is limit 1/4[f(x)]^4 as x approaches 0?

stepladder [879]

Answer:

$\displaystyle 64$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Rule [Variable Direct Substitution Exponential]: $\displaystyle \lim_{x \to c} x^n = c^n$

Limit Property [Multiplied Constant]: $\displaystyle \lim_{x \to c} bf(x) = b \lim_{x \to c} f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \lim_{x \to 0} f(x) = 4$

Step 2: Solve

Rewrite [Limit Property - Multiplied Constant]: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4} \lim_{x \to 0} [f(x)]^4$
Evaluate limit [Limit Rule - Variable Direct Substitution Exponential]: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4}(4^4)$
Simplify: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = 64$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

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