Answer:
A function f:R→R is periodic if there exists some number t>0 such that
f(x)=f(x+t)
A constant function is periodic since you can take t=1,t=2, etc. (Hint: Hover over the tag "periodic-functions". What do you see?)
The fundamental period of f is the smallest of such t's. Since t cannot be 0, you are looking for the minimum of (0,∞), which does not exist.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The ans will be 16y^2
As 9y^2+7y^2=16y^2
X= -5
Explaination: you subtract 12 from both sides and left with -5
