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2 years ago

How many and what type of solution(s) does the equation have?

Mathematics

1 answer:

zzz [600]2 years ago

3 0

Answer:

2 irrational solutions.

Step-by-step explanation:

6p^2 = 8p + 3

0 = -6p^2 + 8p + 3

The roots are:

p = (2/3) - (8.5)^(1/2)/3, and

p = (2/3) + (8.5)^(1/2)/3

These are irrational numbers.

There are 2 irrational solutions.

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There are three options for fans purchasing a band's new release CD. They can purchase the CD, a premium CD bundle, or a deluxe

cluponka [151]

Answer:

The price of CD's = $15

The price of deluxe bundles = $85

The price of premium bundles. = $ 35 ....

Step-by-step explanation:

Let c represents the number of CD's

Let d represents the number of deluxe bundles

Let p represents the number of premium bundles.

Now according to the given statement:

c = $15

d = c+2p =

d = 15+2p --------equation 1

455c+87p+35d = $12,845 --------equation 2

Now substitute the value of d in equation 2 to find the value of p

455c+87p+35d = $12,845

455(15)+87p+35(15+2p) = $12,845

6825+87p+525+70p=$12,845

Now combine the like terms:

6825+157p+525 = $12,845

Now shift all the like terms to the R.H.S

157p= 12845-6825-525

157p = 5495

Divide both sides by 157

157p/157 = 5495/157

p = 35

Now substitute the value p =35 in equation 1.

d = 15+ 2p

d = 15+2(35)

d = 15+70

d = 85

Therefore we have found that,

The price of CD's = $15

The price of deluxe bundles = $85

The price of premium bundles. = $ 35 ....

4 0

3 years ago

In triangle DEF measurement angle D = 45 degrees meausrement angle E = 63 degrees and EF = 24 inches. What is DE to the nearest

alexandr1967 [171]

Since the angles add to 180°, angle F is 72°.

Using the law of sines,

DF/sin72° = 24/sin45°
x = 32.28

So, did you just guess at A?

This is just an answer from another website, but it should still work.

7 0

2 years ago

Read 2 more answers

Can any negative integer be greater than a positive integer explain

Keith_Richards [23]

No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.

Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

$y < 0 < x$