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bulgar [2K]
3 years ago
6

** HELP ASAPP ** how do u do this!!! (image bellow)

Mathematics
2 answers:
Nikitich [7]3 years ago
7 0

Answer:

x/2 + y/3 = 1

Step-by-step explanation:

using this formula

x/a + y/b = 1 , where a and b are the coordinates of x and y axes respectively.

Iteru [2.4K]3 years ago
7 0

Solution:

<u>6a) Slope = y₂ - y₁/x₂ - x₁ </u>

  • => Slope = 3 - 6/2 - (-4)
  • => slope = -3/6 = -1/2

6b) y-intercept = 4 (According to the graph)

6c) The equation formed is y = -x/2 + 4.

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Ryan practiced 43.2 minutes on Monday on his violin. Tuesday, he practiced 37.48 minutes. If he practiced a total of 114.34 minu
Nesterboy [21]

Answer:

Ryan practiced 33.66 minutes on Wednesday

Step-by-step explanation:

You do 43.2+37.48 and it equals 80.68

Then you do 114.34-80.68 which equals 33.66

6 0
3 years ago
Ann sleeps 8 hours a night. write an expression for the number of hours Ann sleeps in n nights
Aleks [24]
It's 8n meaning 8 times n (8*n) so for example for 5 nights she would sleep : 8*5 = 40 hours in total.
6 0
3 years ago
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Determine the next step for solving the quadratic equation by completing the square.
nexus9112 [7]

\qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

the idea behind the completion of the square is simply using a perfect square trinomial,  hmmm usually we do that by using our very good friend Mr Zero, 0.

if we look at the 2nd step, we have a group as x² - x, hmmm so we need a third element, which will be squared.

keeping in mind that the middle term of the perfect square trinomial is simply the product of the roots of "a" and "b",  so in this case the middle term is "-x", and the 1st term is x², so we can say that

\stackrel{middle~term}{2(\sqrt{x^2})(\sqrt{b^2})~}~ = ~~\stackrel{middle~term}{-x}\implies 2xb~~ = ~~~~ = ~~-x \\\\\\ b=\cfrac{-x}{2x} \implies b=-\cfrac{1}{2}

so that means that our missing third term for a perfect square trinomial is simply 1/2, now we'll go to our good friend Mr Zero, if we add (1/2)², we have to also subtract (1/2)², because all we're really doing is borrowing from Zero, so we'll be including then +(1/2)² and -(1/2)², keeping in mind that 1/4 - 1/4 = 0, so let's do that.

-3~~ = ~~-2\left[ x^2-x+\left( \cfrac{1}{2} \right)^2 ~~ - ~~\left( \cfrac{1}{2} \right)^2\right]\implies -3=-2\left(x^2-x+\cfrac{1}{4}-\cfrac{1}{4} \right) \\\\\\ -3=-2\left(x^2-x+\cfrac{1}{4} \right)+(-2)-\cfrac{1}{4}\implies -3=-2\left(x^2-x+\cfrac{1}{4} \right)+\cfrac{1}{2} \\\\\\ -3-\cfrac{1}{2}=-2\left(x^2-x+\cfrac{1}{4} \right)\implies -\cfrac{7}{2}=-2\left(x-\cfrac{1}{2} \right)^2\implies \cfrac{7}{4}=\left(x-\cfrac{1}{2} \right)^2

~\dotfill\\\\ \pm\sqrt{\cfrac{7}{4}}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}+\cfrac{1}{2}=x \implies \cfrac{\pm\sqrt{7}+1}{2}=x

8 0
2 years ago
WILL GIVE BRAINLIEST!! Rhombus ABCD has perimeter 148, and one of its diagonals has length 24. How long is the other diagonal?
natali 33 [55]
Answer: 70 units. = 37 units. The diagonals bisect each other at right angles so when we draw the 2 diagonals we have 4 congruent right-angled triangles.
5 0
3 years ago
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Solve 2sin(2x) - 2sinx +2sqrt3 cosx - sqrt3 = 0
SashulF [63]

Answer:

2sin(2x)-2sinx+2sqrt3cosx-sqrt3 = 0

-----

4sin(x)cos(x) - 2sin(x) + 2sqrt(3)cos(x) - sqrt(3) = 0

-----

Factor:

2sin(x)[2cos(x)-1] + sqrt(3)[2cos(x)-1] = 0

-----

[2cos(x)-1][2sin(x)+sqrt(3)] = 0

Solve:

2cos(x)-1 = 0 or 2sin(x)+sqrt(3) = 0

cos(x) = 1/2 or sin(x) = -sqrt(3)/2

x = +/-pi/3 or x = -pi/3 or (4/3)pi

hope this helps!

3 0
3 years ago
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