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2 years ago

( x + 2 ) ( 3x^ - 4x + 5)

Mathematics

2 answers:

raketka [301]2 years ago

7 0

Answer:

(x+2)(5+3x^n-4x)

Step-by-step explanation:

8090 [49]2 years ago

5 0

Answer:

5x+3x^-2+-6x^-3+10

Step-by-step explanation:

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If BC = 5, DE = 9, and AB = 4, what is the length of AD? 7 8 7.2 7.5

steposvetlana [31]

There are two triangles here: ABC and ADF. These triangles are similar, and thus proportional. So, we can set up a proportion between the left side of each triangle and the base of each triangle.

AB / AD = BC / DE

4 / (4 + BD) = 5 / 9

---AD is made up of AB and DB. We know AB, but not BD, so we need to find its value to find the length of AD.

5(4 + BD) = 9 x 4

20 + 5BD = 36

5BD = 16

BD = 3.2

AD = AB + BD

AD = 4 + 3.2

AD = 7.2

Hope this helps!

8 0

2 years ago

PLZ HELP!!! WILL MARK THE BRAINLIEST IF ANSWER IS CORRECT.

slavikrds [6]

lynville is the correct answer i think

6 0

3 years ago

Use the distributive property to write the products in standard form (48+24)÷6 .

Lorico [155]

AnswerI think 11

Step-by-step explanation:48+24=66 and that divided by 6 is 11 sorry if it’s wrong I think we start form 48+24 though. :)

3 0

1 year ago

Solve 5x - c = k for x Answers above

Rama09 [41]

Answer:

x = ( k+c)/5

Step-by-step explanation:

5x - c = k

Add c to each side

5x -c+c = k+c

5x = k+c

Divide by 5

5x/5= ( k+c)/5

x = ( k+c)/5

5 0

2 years ago

Read 2 more answers

Write the equation in slope-intercept form through the point (-4, -7) and is perpendicular to the line y = -(7/4)x + 4 and graph

Scilla [17]

You have to write the equation for a line that crosses the point (-4, -7) and is perpendicular to the line

$y=-\frac{7}{4}x+4$

When you have to determine a line that is perpendicular to a known line, you have to keep in mind that the slope of the perpendicular line will be the negative inverse of the first one.

If for exampla you have two lines, the first one being:

$y_1=mx+b$

And the second one, that is perpedicular to the one above:

$y_2=nx+c$

The slope of the second one is the negative inverse of the first one:

$n=-\frac{1}{m}$

The slope of the given line y=-7/4+4 is m=-7/4

So the slope of the perpendicular line has to ve the inverse negative of -7/4

$\begin{gathered} n=-(-\frac{4}{7}) \\ n=\frac{4}{7} \end{gathered}$

Considering it has to pass through the point (-4,-7) and that we already determined its slope, you can unse the point slope formula to determine the equation of the perpendicular line:

$y-y_1=m(x-x_1)$

replace with the coordinates of the point and the slope and calculate:

$\begin{gathered} y-(-7)=\frac{4}{7}(x-(-4)) \\ y+7=\frac{4}{7}(x+4) \\ y+7=\frac{4}{7}x+\frac{16}{7} \end{gathered}$

Subtract 7 to both sides of the equation to write it in slope-intercept form:

$\begin{gathered} y+7-7=\frac{4}{7}x+\frac{16}{7}-7 \\ y=\frac{4}{7}x-\frac{33}{7} \end{gathered}$

Now you can graph both lines

8 0

9 months ago