Area=1/2bh
add them
(1/2)ab+(1/2)c^2+(1/2)ab=
ab+(1/2)c^2
ab+(1/2)(a^2+b^2)
not sure which option to pick there are different preferences on what counts as 'simplified'
4. find area
area=LW
area=105*45=4725
depends on the area of the signs
answer is
4725/(areaof1sign)
anyway, round down your answer because you will have an incomplete sign if you don't
5. area=pir^2
1/2 of it is
area=1/2pir^2
area=(1/4)^2pir^2
area=pi((1/4)r)^2
the radius is now 1/4 of what it was originally, meaning that the diameter is also 1/4 of what it is now
we need to know diamater
answer is 1/4 of current diameter
3. unclear
4. area of 1 sign not given, answer is 4725/(areaof1sign), rounded DOWN to nearest integer
5. (404 error, diameter not found) answer is 1/4 of current diameter
Answer:
(22,0)
Step-by-step explanation:
1. Select any two points given and find their slope (rise/run)
(-38, 40) and (-23, 30)
slope = 
= - 2/3
2. Use the slope and one of the points to create an equation of the line in the format y = mx + b, where m = slope and b = y-intercept.
y = mx + b ⇒ 40 = -2/3 (-38) + b
3. Solve for b
40 = -2/3 (-38) + b
40 = 76/3 + b
40 - 76/3 = b
b = 44/3
4. To find the x-intercept, set y = 0, and solve.
y = -2/3 x + 44/3
0 = -2/3 x + 44/3
2/3 x = 44/3
x = 22
Hope this helped!
Answer:
Step-by-step explanation:
<u>Quadratic Function</u>
Standard Form of Quadratic Function
The standard representation of a quadratic function is:
where a,b, and c are constants.
When the zeros of f (x1 and x2) are given, it can be written as:
f(x)=a(x-x1)(x-x2)
Where a is a constant called the leading coefficient.
We are given the two roots of f: x1=-3 and x2=4, thus:
f(x)=a(x+3)(x-4)
We also know that f(5)=8, thus:
f(5)=a(5+3)(5-4)=8
Operating:
a(8)(1)=8
Solving:
a=1
The function is:
f(x)=1(x+3)(x-4)
Operating:
Answer:
Kenny is 18 years old Andrew is 10 years old Tim is 30 years old and Cameron is 5 years old
Step-by-step explanation:
Let a be Kenny's age , b be Andrew's age , c be Tim's age , d be Cameron's age
( b < a , b<c , d<b)
Kenny is 8 years older than Andrewn = > a = b + 8 (1)
Tim is 3 times as old as Andrew => c = 3 . b (2)
Cameron is 5 years younger than Andrew => d = b-5 (3)
The combined age of the four is 63 => a+b+c+d = 63 (4)
(1),(2),(3),(4) => b+8 + b + 3b + b-5 = 63 <=> 6b + 3 = 63 <=> b = 10
=> a= 10+8 =18, c = 3 . 10 = 30, d= 5
In step 1 , it's commutative property of addition
hope it helps
