We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
18 - 5.7 = 12.3
12.3 - 8.8 = 3.5
3.5 to a fraction = 3 1/2
So the answer = 3 1/2
Hope this helps >.<
Answer: v= 4.34
Step-by-step explanation:
5.4*4.9= 6.1v
26.46/6.1 = v
4.34= v
1. Find angle Y. Since the interior angles of a triangle must add up to 180 deg., we have 180 - (98+24) = 58 deg.
Apply the Law of Sines to determine the lengths of sides r and t:
r 7.9 t
--------- = --------- = ---------
sin 98 sin 58 sin 24
Then r = (7.9 sin 98)/ (sin 58) = 9.22. This matches r in the 2nd choice. Determine t using the same method: t = 7.9sin 24 / sin 58.
Does your t value match that in the 2nd possible answer?
Answer:
3
Step-by-step explanation:
