Question

One factor in flood safety along a levee is the area that will absorb water should the levee break. The coordinates that make up the boundary area are (0,0), (2.8, 2.1), and (4.3, 4.4). What is the area of the land that would absorb the area?
a) 1.65 mi^2.
b) 9.03 mi^2.
c) 1.1 mi^2.
d) 10.68 mi^2

Answer 1

The area of the land that would absorb the area is 1.65 mi^2.

 

Levee is an embankment built to prevent the overflow of a river.

 

The correct answer between all the choices given is the first choice or letter A. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

Answer 2

Let

$A(0,0)\\ B (2.8, 2.1)\\C(4.3, 4.4)$

using a graph tool

see the attached figure

The figure is a triangle

we know that

The Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Hero's Formula is equal to

$Area=\sqrt{p*(p-a)*(p-b)*(p-c)}$

where

p is  is half the perimeter of the triangle

 a,b,c are the lengths of the sides of a triangle

so

Step $1$

Find the length sides of the triangle

a) Find the distance AB

$d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}$

Substitute

$d =\sqrt{(2.1-0)^{2} +(2.8-0)^{2}}$

$d =3.5\ mi}$

b) Find the distance AC

$d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}$

Substitute

$d =\sqrt{(4.4-0)^{2} +(4.3-0)^{2}}$

$d =6.15\ mi}$

c) Find the distance BC

$d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}$

Substitute

$d =\sqrt{(4.4-2.1)^{2} +(4.3-2.8)^{2}}$

$d =2.75\ mi}$

Step $2$

Find the perimeter of the triangle

$Perimeter= 3.5+6.15+2.75 =12.4\ mi$

Find the half of the perimeter

$p=\frac{12.4}{2} = 6.2\ mi$

Step $3$

Find the area of the triangle

$Area=\sqrt{6.2*(6.2-3.5)*(6.2-6.15)*(6.2-2.75)}$

$Area=\sqrt{6.2*(2.7)*(0.05)*(3.45)}$

$Area= 1.69\ mi^{2}$

therefore

the answer is the option

a) 1.65 mi^2.