Answer: x = 17/3 or 5 2/3
Step-by-step explanation:
Let the number be x
ATQ
6(x -4) = 10
6x-24 = 10
6x = 10+24
6x = 34
x = 34/6
x = 17/3
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Answer: Q=1/2p+15,= p=2q-30= Slope = 1.000/2.000 = 0.500
p-intercept = -30/1 = -30.00000
q-intercept = 30/2 = 15
Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
p-(2*q-30)=0
Solve p-2q+30 = 0
we have an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).
"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.
In this formula :
y tells us how far up the line goes
x tells us how far along
m is the Slope or Gradient i.e. how steep the line is
b is the Y-intercept i.e. where the line crosses the Y axis
The X and Y intercepts and the Slope are called the line properties. We shall now graph the line p-2q+30 = 0 and calculate its properties
Notice that when p = 0 the value of q is 15/1 so this line "cuts" the q axis at q=15.00000
q-intercept = 30/2 = 15
When q = 0 the value of p is -30/1 Our line therefore "cuts" the p axis at p=-30.00000
p-intercept = -30/1 = -30.00000
Slope is defined as the change in q divided by the change in p. We note that for p=0, the value of q is 15.000 and for p=2.000, the value of q is 16.000. So, for a change of 2.000 in p (The change in p is sometimes referred to as "RUN") we get a change of 16.000 - 15.000 = 1.000 in q. (The change in q is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)
Slope = 1.000/2.000 = 0.500
Answer:
3
Step-by-step explanation:
Answer:
6 square root of 2
Step-by-step explanation:
sin theta = opposite / hypotenuse
sin 45 = 6/x
Multiply by x
x sin 45 = 6
Divide by sin 45
x sin 45/ sin 45 = 6 / sin 45
x = 6/ sin 45
x = 6/ (1/sqrt(2))
x = 6 sqrt(2)
Assuming you are focusing on the square only, then the answer is 9 inches.
You take the square root of 81 to get 9. Notice how 9^2 = 9*9 = 81. So if you're not familiar with square roots, then think backwards in a sense to get the answer.
