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strojnjashka [21]
2 years ago
12

PLEASE HELP!!! GIVING 65 POINTS I NEED HELP NOW!!! !The table shows values for functions f(x) and g(x) .

Mathematics
2 answers:
Strike441 [17]2 years ago
8 0

Answer: Given f ( x ) = 2x + 1 and g ( x ) = x2

+ 2x – 1 find ( f + g ) ( x ) and

( f + g ) ( 2 )

Solution

Step 1. Find ( f + g ) ( x )

Since ( f + g ) ( x ) = f ( x ) + g ( x ) then;

( f + g ) ( x ) = ( 2x + 1 ) + (x2

+ 2x – 1 )

= 2x + 1 + x2

+ 2x – 1

= x

2

+ 4x

Step-by-step explanation:

Archy [21]2 years ago
8 0

Answer:

X=5

X=2

X=0

Step-by-step explanation:

Its right i go to k12

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What are the greatest commom factor of 2x2x3x5 and 2x3x3x5​
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8 0
3 years ago
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In a goodness-of-fit test, the null hypothesis states that the data came from a normally distributed population. The researcher
marta [7]

Answer:

Solution: C) 7.815

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8 0
3 years ago
Suppose you buy 4 buckets of apples and 5 buckets of peaches for $64. If you bought 8
Sophie [7]

Option D is the correct answer.

Step-by-step explanation:

Step 1 :

Let A represent the cost of one bucket of apple and P represent the cost of one bucket of peaches.

So we have ,

4 buckets of apples and 5 buckets of peaches for $64

8  buckets of apples and 3 buckets of peaches for $72

Writing this in the equation form we have,

4A + 5P = 64

8A + 3P = 72

Step 2:

Solving for the above 2 equations we can get the required costs

Equation 1 is

4A + 5P = 64 , Multiplying this by 2 we have 8A + 10P = 128

Equation 2  = 8A + 3P = 72

Subtracting both we have , 7p = 56 = > P = 8

Substituting this in equation 1 we have

8A + 80 = 128 => A = 6

Hence the cost of one bucket of apple is $6 and the cost of one bucket of apple is $8.

Option D is the correct answer.

3 0
3 years ago
Read 2 more answers
Please help.
serious [3.7K]

The number of throws that the player make X follows binomial distribution.

The probability that the player makes x throws out of eleven throws is

P(X=x)=C(x,11)0.5^x(0.5)^{11-x}=C(x,11)0.5^{11}

The probability that the player makes at most nine out of eleven free throws

is

\sum_{x=0}^9C(x,11)0.5^{11}=1-\sum_{x=10}^{11}C(x,11)0.5^{11}\\ =1-C(10,11)0.5^{11}-C(11,11)0.5^{11}=1-\frac{12}{2^{11}} \\ =1-\frac{3}{512} =\frac{509}{512}

Correct choice is (B).

8 0
3 years ago
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