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strojnjashka [21]
2 years ago
12

PLEASE HELP!!! GIVING 65 POINTS I NEED HELP NOW!!! !The table shows values for functions f(x) and g(x) .

Mathematics
2 answers:
Strike441 [17]2 years ago
8 0

Answer: Given f ( x ) = 2x + 1 and g ( x ) = x2

+ 2x – 1 find ( f + g ) ( x ) and

( f + g ) ( 2 )

Solution

Step 1. Find ( f + g ) ( x )

Since ( f + g ) ( x ) = f ( x ) + g ( x ) then;

( f + g ) ( x ) = ( 2x + 1 ) + (x2

+ 2x – 1 )

= 2x + 1 + x2

+ 2x – 1

= x

2

+ 4x

Step-by-step explanation:

Archy [21]2 years ago
8 0

Answer:

X=5

X=2

X=0

Step-by-step explanation:

Its right i go to k12

You might be interested in
-4.5 + 4.4 + ____ = 0
jenyasd209 [6]

Answer:

A, -6. 7 + 6.8.

Step-by-step explanation:

-4.5 + 4.4 = -0.1

-0.1 - 6.7 = -6.8

-6.8 + 6.8 = 0!!!

I hope this helps!

4 0
3 years ago
.John has $40. He will use some of the money to buy books, and he wants to have at least $10 left to put in his savings account.
Crank

Answer:

The required inequality is 40-6b\leq 10.

Jhon can buy at most 5 books.

Step-by-step explanation:

Consider the provided information.

Part(A)

Let b represent the number of books John buys.

He wants at least $10 in his savings account which means if we subtract the cost of books from $40 we have at least $10 left.

40-6b\leq 10

The required inequality is 40-6b\leq 10.

Part(B)

40-6b\leq 10

-6b\leq 10-40

b \leq\frac{30}{6}

b\leq 5

Part(C):  Jhon can buy at most 5 books.

3 0
3 years ago
An account begins the year with a
jenyasd209 [6]

s = c(1 + in) \\ s = 4000(1 + 0.03 \times 1)

s = 4120.00

<h2>Option: A</h2>
4 0
2 years ago
What are the amplitude, period, and phase shift of the given function? f(t)=-1/2sin(3t-2pi)
Romashka [77]

Answer:

The amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

Step-by-step explanation:

The given function is

f(t)=-\frac{1}{2}\sin (3t-2\pi)      .... (1)

The general form of sine function is

F(t)=A\sin (Bt-C)+D                 ....(2)

where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.

On comparing (1) and (2), we get

A=-\frac{1}{2}

B=3

C=2\pi

D=0

So,

amplitude=|A|=\frac{1}{2}

period=3

\text{phase shift}=\frac{2\pi}{3}

Therefore amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

8 0
4 years ago
Two boxes of identical birthday candles are pictured: a 2-ounce box and a 6-ounce box. There are 96 candles in the large box. Ho
Lostsunrise [7]
Ratio of large box
96:6
Thus 96/6 = 16

Small box 
2*16 = 32
There are 32 candles in the small box.


5 0
3 years ago
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