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2 years ago

HELPPPPP MEEE PLEASEE

Mathematics

1 answer:

AURORKA [14]2 years ago

5 0

answer : 11

explanation: a2

$a ^{2} + 3b \div c - 2d \\ {3 }^{2} + 3(8) \div 2 - 2(5) \\ 9 + 24 \div 2 - 10 \\ 9 + 12 - 10 \\ 21 - 10 \\ = 11$

a2+3b÷c−2d
3^2+3(8)÷2−2(5) substitute the values in place of the letters
9+24÷2−10 use the relevant equation and find the value
9+12−10 according to the BODMAS u have to divide first (24÷2=12)
21−10=11

incase u didn't know what BODMAS is

B - brackets

O- order of powers

D-division

M-multiplication

A-addition

S-subraction

hope this helps☆☆☆

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Let x1 = 12, y1 = 15, and y2 = 3. Let y vary inversely with x. Find x2.

vladimir1956 [14]

Answer:

x2 = 60

Step-by-step explanation:

If the variables x and y are inversely proportional, the product x * y is a constant.

So using x1 and y1 we can find the value of this constant:

$x1 * y1 = k$

$12 * 15 = k$

$k = 180$

Now, we can use the same constant to find x2:

$x2 * y2 = k$

$x2 * 3 = 180$

$x2 = 180 / 3 = 60$

So the value of x2 is 60.

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3 years ago

Can you answer this please?

Nat2105 [25]

Answer: 112.5 square units

Step-by-step explanation:

I think:

For the triangle:

1/2base(height) = 1/2(9)(7)= 31.5 sq. Units

For the small rectangle:

Length x width= 3 x 9 = 27 sq. Units

For the larger rectangle:

The length must be 16 - 7 - 3 = 6

So length x width = 6 x 9 = 54 sq units

Now add them together:

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7 0

3 years ago

The factorization of x2 + 3x – 4 is modeled with algebra

meriva

Option C: (x+4) and (x-1) are the factors of the equation

Explanation:

Given that the equation is $x^{2} +3x-4$

We need to determine the factors of the equation.

Splitting the middle term, we get,

$x^{2} +4x-x-4$

Grouping the terms, we have,

$x(x+4)-1(x+4)$

Let us factor out the term (x+4), we have,

$(x+4)(x-1)$

Thus, the factors of the equation are (x+4) and (x-1)

Hence, Option C is the correct answer.

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3 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

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