A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
(3/5)³
=(3³)/(5³)
=27/125
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As:
3*3*3=27
And:
5*5*5=125
Answer:
54 degrees
Step-by-step explanation:
Answer:
Speed of plane in still air: 490 mile/hour
speed of wind: 70 mile/hour
Step-by-step explanation:
still speed = x wind speed = w
with wind: speed = still + wind
(x+w) * 3 = 1680 ...a
against wind: speed = still - wind
(x-w) * 4 = 1680 ...b
b-a ... 4x-4w-3x-3w = 0
x-7w = 0
x = 7w
substitution: (7w+w)*3 = 1680 8w = 560 wind speed (w) = 70
still speed (x) = 7w = 490 mile/hour
Answer:
34 degrees.
Step-by-step explanation:
Assuming AK is a straight line and being shown angle JDK is right and 90 degrees it can be stated that 4x + (3x-8) = 90 degrees.
Drop the parentheses and get 7x - 8 = 90.
Add 8 to both sides 7x = 98.
Divide both sides by 7, x = 14.
Plug that x value into (3x-8), [3(14)-8] = 34 degrees.
