The measure of arc QS is (4x-18)° what is the value of x?
2 answers:
Answer:
Option C. 49.5°
Step-by-step explanation:
In the given figure arc QS is the diameter of the circle.
Angle formed at semicircle is 90°.
Therefore angle formed at center T will be 180°(∠QPS = 180° which is 2×∠QRS)
Now it is given arc QS = (4x - 18)° and equal to 180°
4x - 18 = 180
4x = 180 + 18 = 198
4x = 198
x = 198/4 = 49.5°
So the answer is 49.5°
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The answer is; begging the question.
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I think it’s repression but i’m not sure
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Bad behavior at lease i think:)
